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kvasek [131]
3 years ago
9

The small, touch-sensitive area at the base of the keyboard on a notebook computer is known as a ________.

Computers and Technology
2 answers:
USPshnik [31]3 years ago
8 0
Trackpad.

(Sheep sheep mr sheep meep)
IrinaK [193]3 years ago
7 0

Answer:

trackpad

Explanation:

You might be interested in
High Frequency Traders are
Alex73 [517]

Answer:

Firms that use high-speed computers and communications networks to execute millisecond trades for themselves

Explanation:

High Frequency traders are different entities that take part in the market that use powerful computers to be able to be fast at answering to news and have a big number of trades. These traders use advance tools to evaluate the markets and anticipate trends quickly to obtain profits from the trades they make. According to this, the answer is that High Frequency Traders are Firms that use high-speed computers and communications networks to execute millisecond trades for themselves.

7 0
3 years ago
You are to calculate the property tax for tax payers. You will ask the county tax clerk if they want to run the program and init
andre [41]

Answer:

Explanation:

The following code is written in Java. It creates the loop as requested and validates the information provided before continuing, if the information is invalid it prints "Invalid Information to the screen" and asks the user to enter the information again. Finally, outputing all the requested information at the end of the program. The code has been tested and the output can be seen in the attached image below.

import java.util.ArrayList;

import java.util.Arrays;

import java.util.Scanner;

class Brainly {

   public static void main(String[] args) {

       Scanner in = new Scanner(System.in);

       int totalValues = 0;

       int totalTaxes = 0;

       int count = 0;

       while(true) {

           int lotNumber, value;

           double tax;

           System.out.println("Would you like to add an Entry: 1=Yes 0=No");

           int answer = in.nextInt();

           if (answer == 1) {

               System.out.println("Please enter lot number: ");

               lotNumber = in.nextInt();

               if ((lotNumber >= 0) && (lotNumber <= 999999)) {

                   System.out.println("Please enter assessed value: ");

                   value = in.nextInt();

                   tax = value * 0.05;

                   System.out.println("Lot Number: " + lotNumber);

                   System.out.println("Property Value: " + value);

                   System.out.println("Property Tax: " + tax);

                   totalTaxes += tax;

                   totalValues += value;

                   count += 1;

               } else {

                   System.out.println("Invalid Lot Number");

               }

           } else {

               break;

           }

       }

       int average = totalTaxes / count;

       System.out.println("Total Property Values: " + totalValues);

       System.out.println("Total Property Taxes: " + totalTaxes);

       System.out.println("Average Property Tax" + average);

   }

}

8 0
3 years ago
Programming challenge description: Write a program that, given two binary numbers represented as strings, prints their sum in bi
Lubov Fominskaja [6]

Answer:

The program to this question can be given as:

Program:

#include<iostream>  //include header file

using namespace std;  

string add(string a, string b)  //define add function

{       //declare variable  

   string result = "";  

   int sum = 0,k,l;      

   cahr x;    

   k= a.size() - 1;

   l = b.size() - 1;  

   while (k>= 0 || l>= 0 || sum == 1) //loop

   {

   //addition 

       sum= sum+ ((k >= 0)? a[k] - '0': 0);  

       sum= sum+ ((l >= 0)? b[l] - '0': 0);

        x=sum%2;

      result=(x+'0') +result;

  // Compute carry

       sum =sum/ 2;  

       // Move to next digits  

       k--;  

       l--;  

   }  

   return result; //return value

}

int main()  //main method  

{  

   string a,b;  //string variable

   cout<<"Enter first binary digit: ";  //message.

   cin>>a;     //input from user

   cout<<"Enter Second binary digit: ";  //message.

   cin>>b;     //input from user

   cout <<"Addition :"<<add(a, b)<<endl; //print addition

   return 0;  

}

Output:

Enter first binary digit: 1101

Enter Second binary digit: 100

Addition :10001

Explanation:

In the above c++ program first, we include the header file. Then we define the add function in the add function we add two binary digits by passing value as arguments. In this function, we define a variable that is used on the addition of binary numbers. In this function we define the loop in the loop we check if two binary number is 1 then it will print 0 and pass 1 as the carry. after performing addition it will return value. In the main function, we take two binary numbers from the user and pass the value to the function and print function return value.

8 0
3 years ago
Tanner is creating a brochure for his Web-hosting company. He designed the layout and placed a picture in the center of the page
Romashka [77]
Resizing is a very simple process. On the photo editing program, simply click on the image, and if resize handles appear around it, click and drag those to the desired size. If the program has a dedicated resizing or rescaling tool, use it and follow the above instructions. Keep the photo proportionate by holding down the shift key while dragging a corner handle. <span>Tanner has to make sure that his photo his of a high enough resolution to resize. A pixellated or blurry photo will only get worse when scaled up. He also has to make sure he doesn't resize it to be too big or it will also end up pixellated.</span>
5 0
3 years ago
The flagging of an uncommon last name as a spelling error can be stopped by opening the shortcut menu on the first occurrence of
Mice21 [21]

Solution:

The flagging of an uncommon last name as a spelling error can be stopped by opening the shortcut menu on the first occurrence of the name and selecting of ignoring all.

Thus the required right answer is B.

8 0
3 years ago
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