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ioda
3 years ago
12

Need help with last one SOS

Mathematics
1 answer:
Veronika [31]3 years ago
5 0
To find x, substract 72 and 78 from 180 since all triangles are 180°

180 - 72 - 80 = 30

So x = 30

To find y, x and y equal 180 so subtract 30 from 180

180 - 30 = 150

y = 150

x = 30, y = 150
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The Johnsons want to cover their backyard with new grass. Their backyard is rectangular, with a length of 3x – 5 feet and a widt
kolezko [41]

Answer:

Step-by-step explanation:

The formula for determining the area of a rectangle is expressed as

Area = length × width

Their backyard is rectangular, with a length of 3x – 5 feet and a width of 4x – 10 feet. This means that the area of the backyard is

(3x - 5)(4x - 10)

= 12x² - 30x - 20x + 15

= (12x² - 50x + 15) square feet

Their rectangular swimming pool, along with its surrounding patio, has dimensions of x + 8 by x – 2 feet. This means that the area occupied by the swimming pool and its surrounding patio is

(x + 8)(x - 2)

= x² - 2x + 8x - 16

= x² + 6x - 16

Assuming the swimming pool and its surrounding patio will not be covered with new grass, then the area of the region of the yard that they want to cover with new grass is

12x² - 50x + 15 - (x² + 6x - 16)

= 12x² - 50x + 15 - x² - 6x + 16

= 12x² - x² - 50x - 6x + 15 + 16

= 11x² - 56x + 31 square feet

3 0
3 years ago
Calculate the surface area of the three-dimensional objects below.​
Ivenika [448]
The answer is:
____34____
6 0
3 years ago
Need help stat! 100 POINTS
kirill115 [55]

Answer:

the answer is 67 square inches.

8 0
2 years ago
Read 2 more answers
Find the value of the variable.
nalin [4]

Answer:

The variable, y is 11°

Step-by-step explanation:

The given parameters are;

in triangle ΔABC;          {}              in triangle ΔFGH;

Segment \overline {AB} = 14         {}               Segment \overline {FG} = 14

Segment \overline {BC} = 27         {}              Segment \overline {GH} = 19

Segment \overline {AC} = 19         {}               Segment \overline {FH} = 2·y + 5

∡A = 32°                       {}                ∡G = 32°

∡A = ∠BAC which is the angle formed by segments \overline {AB} = 14 and \overline {AC} = 19

Therefore, segment \overline {BC} = 27, is the segment opposite to ∡A = 32°

Similarly, ∡G = ∠FGH which is the angle formed by segments \overline {FG} = 14 and \overline {GH} = 19

Therefore, segment \overline {FH} = 2·y + 5, is the segment opposite to ∡A = 32° and triangle ΔABC ≅ ΔFGH by Side-Angle-Side congruency rule which gives;

\overline {FH} ≅ \overline {BC} by Congruent Parts of Congruent Triangles are Congruent (CPCTC)

∴ \overline {FH} = \overline {BC} = 27° y definition of congruency

\overline {FH} = 2·y + 5 = 27° by transitive property

∴ 2·y + 5 = 27°

2·y = 27° - 5° = 22°

y = 22°/2 = 11°

The variable, y = 11°

8 0
2 years ago
Order the values from<br> least to greatest:<br> | -4|,|3|, 0,-1
mrs_skeptik [129]

Answer: -4, -1, 0, 3

8 0
3 years ago
Read 2 more answers
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