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SCORPION-xisa [38]
2 years ago
7

Plzzzzzzzzzzzzzzzzzzzzzz

Mathematics
1 answer:
fredd [130]2 years ago
3 0

Answer:

1. 4e^2

2. 2c^2

3. 3a^4

Step-by-step explanation:

1. 12e^5/3e^3.

Simplify:

12/3=4

e^5/e^3=3^2.

4e^2.

2. 8c^3d^2/4cd^2

d^2 cancels out

c^3/c^1=c^2

8/4=2

2c^2.

3. 4a*6a^5/8a^2.

First combine 4a*6a^5

4a^1*6a^5

24a^6.

24a^6/8a^2

3a^4.

Hope this helps you :D

Have a great day :D

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Given that GI = 53, and
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We can establish the following equality statement to solve for x:

GH + HI = GI
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Combine like terms:
5x - 7 = 53

Add 7 to both sides:
5x - 7 + 7 = 53 + 7
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Divide both sides by 5 to solve for x:
5x/5 = 60/5

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Substitute the value of x into the equality statement to verify if it is the correct value for x:

GH + HI = GI
3x - 11 + 2x + 4 = 53

3(12) - 11 + 2(12) + 4 = 53
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Therefore:
GH = 3x - 11
GH = 3(12) - 11
GH = 25

HI = 2x + 4
HI = 2(12) + 4
HI = 28

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