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Nady [450]
3 years ago
8

of the 150 people surveyed seven out of 10 said they owned at least one pet how many of the people surveyed owned pets

Mathematics
2 answers:
suter [353]3 years ago
4 0
15 times 7, which is 105.
Klio2033 [76]3 years ago
4 0
15 times seven which is 105
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A store has 80 modems in its inventory, 30 coming from source a and the remainder from source
Mrrafil [7]
The number of defective modems in the inventory is 20%⋅ 30 + 8%⋅ 50 = 10 (out of 80). Note that the number of defectives in the inventory is fixed, i.e., we are not told that there is 1 8 probability that a modem in the inventory is defective, but rather that exactly 1 8 of all modems are defective. The probability that exactly two modems in a random sample of five are defective is = 0.102
5 0
2 years ago
What is x+9=2(x_1)^2 in the form of ax^2+bx +c=0
Naddik [55]
<span>x + 9 = 2(x - 1)^2
x + 9 = 2(x^2 - 2x + 1)
x + 9 = 2x^2 - 4x + 2
</span>2x^2 - 4x + 2 - x - 9 = 0
2x^2 - 5x -7 =0
7 0
3 years ago
Put a digit in the gap, such that the answer is a whole number:
Makovka662 [10]

Answer: The possible digits are 2,5 and 8

Step-by-step explanation:

3x +486 = 100_

From the equation in the question, we are looking for a digit to put in the gap after 100 to make sure that when we solve the question, x will be a whole number.

Therefore, since it's a single digit required, the possible digits will be from 0 to 9.

Now, from divisibilty tests, for a number from 2 digits upwards to be divisible by 3, the sum of its digits has to be divisible by 3.

Going back to the question, let's divide each term by 3 to get ;

3x/3 + 486/3 = 100_ to give ;

x + 162 = 100_ /3

Now for x to be a whole number, the value on the right hand side must be a whole number.

Therefore, since we know that for a 2 digits and above number to be divisible by 3,it's sum must be divisible by 3. We can plug in any of the digits from 0-9 into the gap and add up.

For 0; 1+0+0+0= 1

For 1; 1+0+0+1 = 2

For 2; 1+0+0+2= 3

Following the same addition pattern for digits 3,4,5,6,7,8and 9, we'll get sum of 4,5,6,7,8,9 and 10 respectively.

Inspecting the above, the only additions that are divisible by 3 are when the digit is; 2,5 and 8

6 0
2 years ago
Given: If X, then Y. If Y, then Z. Y is true. So:
8_murik_8 [283]

Answer:

The answer is "X is unknown, Z is true".

Step-by-step explanation:

In the given question option is missing so, the correct answer to this question can be defined as follows:

  • In this question if X is given, then y means depends upon X.
  • If y is given, then z depends on y, that's why in this question  Y and Z are true. but X is unknown.  
7 0
2 years ago
Watching tv: in 2012, the general social survey asked a sample of 1310 people how much time they spend\t watching tv each day. T
gayaneshka [121]

Answer:

a) Null hypothesis:\mu \geq 3  

Alternative hypothesis:\mu < 3  

This hypothesis test is a left tailed test.

b) t=\frac{2.8-3}{\frac{2.6}{\sqrt{1310}}}=-2.784  

The p value for this case can be calculated with this probability:  

p_v =P(z  

We can conduct the test with the Ti84 using the following steps:

STAT>TESTS>T-test>Stats

We input the value \mu_o =3, \bar X= 2.8, s_x = 2.6, n=1310 and for the alternative we select < \mu_o. Then press Calculate.

And we got the same results.  

Step-by-step explanation:

Information given

\bar X=2.8 represent the sample mean

s=2.6 represent the population standard deviation  

n=1310 sample size  

\mu_o =3 represent the value to test

\alpha=0.5 represent the significance level for the hypothesis test.  

t would represent the statistic

p_v represent the p value for the test

Part a) System of hypothesis

We want to test if the true mean is less than 3, the system of hypothesis would be:  

Null hypothesis:\mu \geq 3  

Alternative hypothesis:\mu < 3  

This hypothesis test is a left tailed test.

Part b

The statistic is given by:

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}} (1)  

Replacing the info given we got:

t=\frac{2.8-3}{\frac{2.6}{\sqrt{1310}}}=-2.784  

The p value for this case can be calculated with this probability:  

p_v =P(z  

We can conduct the test with the Ti84 using the following steps:

STAT>TESTS>T-test>Stats

We input the value \mu_o =3, \bar X= 2.8, s_x = 2.6, n=1310 and for the alternative we select < \mu_o. Then press Calculate.

And we got the same results.  

6 0
3 years ago
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