of the 150 people surveyed seven out of 10 said they owned at least one pet how many of the people surveyed owned pets

Which choice is the solution to the inequality below?

Georgia [21]

<h3>hello!</h3>

In order to solve this inequality, we should divide both sides by 9:-

$\sf{9x < 72}$

Why 9? Because x is multiplied by 9, and we need to isolate x in order to find its value.

$\sf{x < 8}$

Hence, that's the solution to the inequality.

<em>It also means that the numbers less than 8 will satisfy the given inequality (make the inequality true)</em>

(Option C is correct :) )

Hope everything is clear; if you need any explanation/clarification, kindly let me know, and I will comment and/or edit my answer :)

8 0

2 years ago

Read 2 more answers

A car drives east along a road at a constant speed of 46 miles per hour. At 4:00 P.M., a truck is 264 miles away, driving west a

sveticcg [70]

Answer:

The speed of the truck is 42 mph

Step-by-step explanation:

we know that

The speed is equal to divide the distance by the time

Let

s -----> the speed in miles per hour

d ----> the distance in miles

t ----> the time in hours

$s=\frac{d}{t}$

$d=s(t)$

step 1

Find out the distance traveled by the car at 7:00 P.M

we have

$s=46\ \frac{mi}{h}$

$t=7:00 P.M-4:00 P.M=3\ h$

$d=s(t)$

substitute the values

$d=46(3)=138\ mi$

step 2

Find out the speed of the truck

we know that

At 7:00 P.M the distance is equal to

$d=264-138=126\ mi$

$t=7:00 P.M-4:00 P.M=3\ h$

substitute

$s=\frac{126}{3}$

$s=42\ \frac{mi}{h}$

7 0

3 years ago

Solve for m: m + 4 = 5m - 12<br><br> m = 16<br><br> m = 4<br><br> m = 3<br><br> m = -3

kolbaska11 [484]

m + 4 = 5m - 12

Subtract m from both sides.

4 = 4m - 12

Add 12 to both sides

16 = 4m

Divide both sides by 4

m = 4

6 0

3 years ago

Read 2 more answers

Scenario

Elena-2011 [213]

The function that gives the shares received by a post whereby each friend

shares the post a constant multiple of times each day is exponential.

<h3>Responses;</h3>

Ben's social media post: <u>2 × 3ⁿ</u>

Carter's social media post: <u>10 × 2ⁿ</u>

<h3>Methods by which the above expressions are obtained:</h3><h3 /><h3>Ben's social media posts;</h3><h3 /><h3>Given:</h3>

The given table of values for Ben's social media post is presented as follows;

$\begin{tabular}{|c|c|}Day&Number of shares\\0&2\\1&6\\2&18\end{array}\right]$

<h3>Solution:</h3>

The number of shares triples everyday, therefore, the number of shares form a geometric progression, with a common ratio of r = 3, and a first term of <em>a</em> = 2

The function for the number of shares of Ben's post is, tₙ = a·rⁿ

Which gives;

Ben's social media post shares on day <u><em>tₙ</em></u><u> = 2·3ⁿ</u>

<h3>Carter's social media posts;</h3><h3 /><h3>Given;</h3>

Number of friends Carter shared his post with = 10 friends

Number of people each of the 10 friends shared with each day = 2 people

<h3>Solution;</h3>

The exponential function for number of shares received by Carter is therefore, <u>tₙ = </u><u>10×2ⁿ</u>

Carter's social media post shares on day <em>n</em>: <u>10 × 2ⁿ</u>

Learn more about exponential functions here:

brainly.com/question/1530446

5 0

2 years ago

A large operator of timeshare complexes requires anyone interested in making a purchase to first visit the site of interest. His

morpeh [17]

Answer:

There is a 21.053% probability that this person made a day visit.

There is a 39.474% probability that this person made a one night visit.

There is a 39.474% probability that this person made a two night visit.

Step-by-step explanation:

We have these following percentages

20% select a day visit

50% select a one-night visit

30% select a two-night visit

40% of the day visitors make a purchase

30% of one night visitors make a purchase

50% of two night visitors make a purchase

The first step to solve this problem is finding the probability that a randomly selected visitor makes a purchase. So:

$P = 0.2(0.4) + 0.5(0.3) + 0.3(0.5) = 0.38$

There is a 38% probability that a randomly selected visitor makes a purchase.

Now, as for the questions, we can formulate them as the following problem:

What is the probability of B happening, knowing that A has happened.

It can be calculated by the following formula

$P = \frac{P(B).P(A/B)}{P(A)}$

Where P(B) is the probability of B happening, P(A/B) is the probability of A happening knowing that B happened and P(A) is the probability of A happening.

Suppose a visitor is randomly selected and is found to have made a purchase.

How likely is it that this person made a day visit?

What is the probability that this person made a day visit, given that she made a purchase?

P(B) is the probability that the person made a day visit. So $P(B) = 0.20$

P(A/B) is the probability that the person who made a day visit made a purchase. So $P(A/B) = 0.4$

P(A) is the probability that the person made a purchase. So $P(A) = 0.38$

So

$P = \frac{P(B).P(A/B)}{P(A)} = \frac{0.4*0.2}{0.38} = 0.21053$

There is a 21.053% probability that this person made a day visit.

How likely is it that this person made a one-night visit?

What is the probability that this person made a one night visit, given that she made a purchase?

P(B) is the probability that the person made a one night visit. So $P(B) = 0.50$

P(A/B) is the probability that the person who made a one night visit made a purchase. So $P(A/B) = 0.3$

P(A) is the probability that the person made a purchase. So $P(A) = 0.38$

So

$P = \frac{P(B).P(A/B)}{P(A)} = \frac{0.5*0.3}{0.38} = 0.39474$

There is a 39.474% probability that this person made a one night visit.

How likely is it that this person made a two-night visit?

What is the probability that this person made a two night visit, given that she made a purchase?

P(B) is the probability that the person made a two night visit. So $P(B) = 0.30$

P(A/B) is the probability that the person who made a two night visit made a purchase. So $P(A/B) = 0.5$

P(A) is the probability that the person made a purchase. So $P(A) = 0.38$

So

$P = \frac{P(B).P(A/B)}{P(A)} = \frac{0.3*0.5}{0.38} = 0.39474$

There is a 39.474% probability that this person made a two night visit.

3 0

3 years ago