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3 years ago

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Given the function g(x) = 8x − 2, compare and contrast g(−2) and g(4). Choose the statement that is true concerning these two va

lues.
The value of g(−2) is larger than the value of g(4).
The value of g(−2) is the same as the value of g(4).
The value of g(−2) is smaller than the value of g(4).
The values of g(−2) and g(4) cannot be compared.

2 answers:

stira [4]3 years ago

4 0

The value of g(−2) is smaller than the value of g(4).

tresset_1 [31]3 years ago

4 0

Answer:

Owo team add tiger 2Owo team add tiger 2Owo team add tiger 2

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Pls help question is in the images

hodyreva [135]

The symbol $\displaystyle{ T_{\ \textless \ -4, 2\ \textgreater \ }(\triangle ABC)$ means that:

we translate ( shift ) the triangle ABC -4 units horizontally and 2 units vertically.

This means that the triangle needs to be shifted 4 units left, and 2 units up.

The only figure which displays such a movement of the triangle (left, up) is the one in the attachment below. That is the answer.

8 0

4 years ago

What would the answer to this question be?<br> A. 40°<br> B. 60°<br> C. 80°<br> D. 100°

Alex777 [14]

Answer:

D. 100°

Step-by-step explanation:

A straight line is 180°. Add 50° and 30° (which is 80°) and subtract the total from 180°.

50 + 30 = 80

180 - 80 = 100

8 0

3 years ago

Read 2 more answers

Svetlana hair is 4 centimeters long. Her hair grows 1.5 cm per month. Svetlana wants her hair to grow so at least 7 cm long. Wri

Andrei [34K]

Let "per month" = m

The inequality is

1.5m + 4 ≥ 7

+ 4: Her hair right now is 4 cm long

1.5m: Her hair grows 1.5 per month (m)

≥ 7: She wants it to be at least 7 or more.

1.5m + 4 ≥ 7 is your answer

hope this helps

3 0

3 years ago

1. Construct a table of values of the following functions using the interval of 5

Morgarella [4.7K]

Complete Question:

Construct a table of values of the following functions using the interval of -5 to 5.

$g(x) = \frac{x^3 + 3x - 5}{x^2}$

Answer:

See Explanation

Step-by-step explanation:

Required

Construct a table with the given interval

When $x = -5$

$g(x) = \frac{x^3 + 3x - 5}{x^2}$ becomes

$g(-5) = \frac{-5^3 + 3(-5) - 5}{-5^2}$

$g(-5) = \frac{-125 -15 - 5}{25}$

$g(-5) = \frac{-145}{25}$

$g(-5) = -5.8$

When $x = -4$

$g(x) = \frac{x^3 + 3x - 5}{x^2}$ becomes

$g(-4) = \frac{-4^3 + 3(-4) - 5}{-4^2}$

$g(-4) = \frac{-64 -12 - 5}{16}$

$g(-4) = \frac{-81}{16}$

$g(-4) = -5.0625$

When $x = -3$

$g(x) = \frac{x^3 + 3x - 5}{x^2}$ becomes

$g(-3) = \frac{-3^3 + 3(-3) - 5}{-3^2}$

$g(-3) = \frac{-27 -9 - 5}{9}$

$g(-3) = \frac{-41}{9}$

$g(-3) = -4.56$

When $x = -2$

$g(x) = \frac{x^3 + 3x - 5}{x^2}$ becomes

$g(-2) = \frac{-2^3 + 3(-2) - 5}{-2^2}$

$g(-2) = \frac{-8 -6 - 5}{4}$

$g(-2) = \frac{-19}{4}$

$g(-2) = -4.75$

When $x = -1$

$g(x) = \frac{x^3 + 3x - 5}{x^2}$ becomes

$g(-1) = \frac{-1^3 + 3(-1) - 5}{-1^2}$

$g(-1) = \frac{-1 + 3 - 5}{1}$

$g(-1) = \frac{-3}{1}$

$g(-1) = -3$

When $x = 0$

$g(x) = \frac{x^3 + 3x - 5}{x^2}$ becomes

$g(0) = \frac{0^3 + 3(0) - 5}{0^2}$

$g(0) = \frac{0 + 0 - 5}{0}$

$g(0) = \frac{- 5}{0}$

<em>g(0) = undefined</em>

When $x = 1$

$g(x) = \frac{x^3 + 3x - 5}{x^2}$ becomes

$g(1) = \frac{1^3 + 3(1) - 5}{1^2}$

$g(1) = \frac{1 + 3 - 5}{1}$

$g(1) = \frac{-1}{1}$

$g(1) = 1$

When $x = 2$

$g(x) = \frac{x^3 + 3x - 5}{x^2}$ becomes

$g(2) = \frac{2^3 + 3(2) - 5}{2^2}$

$g(2) = \frac{8 + 6 - 5}{4}$

$g(2) = \frac{9}{4}$

$g(2) = 2.25$

When $x = 3$

$g(x) = \frac{x^3 + 3x - 5}{x^2}$ becomes

$g(3) = \frac{3^3 + 3(3) - 5}{3^2}$

$g(3) = \frac{27 + 9 - 5}{9}$

$g(3) = \frac{31}{9}$

$g(3) = 3.44$

When $x = 4$

$g(x) = \frac{x^3 + 3x - 5}{x^2}$ becomes

$g(4) = \frac{4^3 + 3(4) - 5}{4^2}$

$g(4) = \frac{64 + 12 - 5}{16}$

$g(4) = \frac{71}{16}$

$g(4) = 4.4375$

When $x = 5$

$g(x) = \frac{x^3 + 3x - 5}{x^2}$ becomes

$g(5) = \frac{5^3 + 3(5) - 5}{5^2}$

$g(5) = \frac{125 + 15 - 5}{25}$

$g(5) = \frac{135}{25}$

$g(5) = 5.4$

<em>Hence, the complete table is:</em>

x ---- g(x)

-5 --- -5.8

-4 --- -5.0625

-3 --- -4.56

-2 --- -4.75

-1 --- -3

0 -- Undefined

1 --- 1

2 -- 2.25

3 --- 3.44

4 --- 4.4375

5 --- 5.4

7 0

3 years ago

Please help im having trouble with this one

andrey2020 [161]

Answer:

22 degrees to the nearest degree.

Step-by-step explanation:

Use the Cosine Rule

3^2 = 5^2 + 7^2 - 2*5*7*cos T

9 = 74 - 70 cos T

cos T = (74-9)/ 70

cos T = 65/70

m < T = 21.8 degrees.

3 0

4 years ago

Read 2 more answers