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3 years ago

HELP ME PLEASE HAVING TROUBLE!

Mathematics

2 answers:

MatroZZZ [7]3 years ago

8 0

<em>Answer,</em>

<em>The top right one. </em>

<em>Explanation,</em>

<em>7 to the 2nd power = 49</em>

<em>The model is showing 49 cubes</em>

<em>In conclusion, that's how I got the answer. </em>

<u><em>Hope this helps :-)</em></u>

guapka [62]3 years ago

6 0

It’s the first one because it has 7 rows and 7 columns which show that it is 7 times 7 or 7^2.

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Find slope of a line perpendicular to each given

statuscvo [17]

82 is the answer now sub to pooi thegreat on yt

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3 years ago

If x – 10 is a factor of x2 – 8x – 20, what is the other factor?

kkurt [141]

Answer:

Step-by-step explanation:

x²-8x-20

=x²-10x+2x-20

=x(x-10)+2(x-10)

=(x-10)(x+2)

second factor is x+2

5 0

3 years ago

Read 2 more answers

A Simple random sample of 100 8th graders at a large suburban middle school indicated that 84% of them are involved with some ty

Setler [38]

Answer: a) (0.755, 0.925)

Step-by-step explanation:

Let p be the population proportion of 8th graders are involved with some type of after school activity.

As per given , we have

n= 100

sample proportion: $\hat{p}=0.84$

Significance level : $\alpha= 1-0.98=0.02$

Critical z-value : $z_{\alpha/2}=2.33$ (using z-value table)

Then, the 98% confidence interval that estimates the proportion of them that are involved in an after school activity will be :-

$\hat{p}\pm z_{\alpha/2}\sqrt{\dfrac{\hat{p}(1-\hat{p})}{n}}$

i.e. $0.84\pm (2.33)\sqrt{\dfrac{0.84(1-0.84)}{100}}$

i.e. $\approx0.84\pm 0.085$

i.e. $(0.84- 0.085,\ 0.84+ 0.085)=(0.755,\ 0.925)$

Hence, the 98% confidence interval that estimates the proportion of them that are involved in an after school activity : a) (0.755, 0.925)

3 0

3 years ago

An internet service provider changes an initial fee of $65 and $18 per hour of labor for office internet installation. Which equ

OlgaM077 [116]

<h2>Answer:</h2><h2>The total cost (C) charged by the internet service provider = $65 + $18(n)</h2>

Step-by-step explanation:

Initial fee charged by the servic eprovider = $65

Cost per hour of labor for office internet installation = $18

The cost per hour be $18

Cost per two hours = 18 * 2 = $36

Cost per n number of hours = $18 (h)

where h represents the number of hours

The total cost (C) charged by the internet service provider = $65 + $18(n)

5 0

3 years ago

The radius of a circle is changing at the rate of 1/π inches per second. At what rate, in square inches per second, is the circl

MAXImum [283]

Answer:

10 square inches per second.

Step-by-step explanation:

The radius of the circle is given by the equation:

r(t) = (1/π in/s)*t

Where time in seconds.

Remember that the area of a circle of radius R is written as:

A = π*R^2

Then the area of our circle will be:

A(t) = π*( (1/π in/s)*t)^2 = π*(1/π in/s)^2*(t)^2

Now we want to find the rate of change (the first derivation of the area) when the radius is equal to 5 inches.

Then the first thing we need to do is find the value of t such that the radius is equal to 5 inches.

r(t) = 5 in = (1/ in/s)*t

5in*(π s/in) = t

5*π s = t

So the radius will be equal to 5 inches after 5*π seconds, let's remember that.

Now let's find the first derivate of A(t)

dA(t)/dt = A'(t) = 2*(π*(1/π in/s)^2*t = (2*π*t)*(1/π in/s)^2

Now we need to evaluate this in the time such that the radius is equal to 5 inches, we will get:

A'(5*π s) = (2*π*5*π s)*((1/π in/s)^2

= (10*π^2 s)*(1/π^2 in^2/s^2) = 10 in^2/s

The rate of change is 10 square inches per second.

4 0

3 years ago