Answer:
The code to this question can be given as:
code:
for(i=1;i<=n;i++) //for loop column
{
for(j=1;j<=i;j++) //for loop for rows
{
printf("*"); // print asterisks
}
printf("\n"); //line break
}
Explanation:
We know that variable i,j, and n is already declared and n variable has initialized a value. So, we write the code that is given above. In this code, we use a nested loop. In this code, we use two loops that are a loop (i)for column and j loop for rows. for print asterisks triangle we use two for loop. For that, we use two-variable (i,j) that is already declared. We assign the value in (i) loop that is 0 and checks that (i) is less than equal to n and increment of (i) by 1. In this loop, we use another loop that is (j) loop. It also starts from 1 and checks that (j) is less than equal to (i)and increment of (j) by 1. In that loop, we print asterisks end of (j) loop. In (i) loop we use ("\n") for line break end of (i) loop.
Answer:
hope this helps. I am also a learner like you. Please cross check my explanation.
Explanation:
#include
#include
using namespace std;
int main()
{
int a[ ] = {0, 0, 0}; //array declared initializing a0=0, a1=0, a3=0
int* p = &a[1]; //pointer p is initialized it will be holding the address of a1 which means when p will be called it will point to whatever is present at the address a1, right now it hold 0.
int* q = &a[0]; //pointer q is initialized it will be holding the address of a0 which means when q will be called it will point to whatever is present at the address a0, right now it hold 0.
q=p; // now q is also pointing towards what p is pointing both holds the same address that is &a[1]
*q=1
; //&a[0] gets overwritten and now pointer q has integer 1......i am not sure abut this one
p = a; //p is now holding address of complete array a
*p=1; // a gets overwritten and now pointer q has integer 1......i am not sure abut this one
int*& r = p; //not sure
int** s = &q; s is a double pointer means it has more capacity of storage than single pointer and is now holding address of q
r = *s + 1; //not sure
s= &r; //explained above
**s = 1; //explained above
return 0;
}
Information can be transferred and passed way easier.
Communication doesn't necessarily mean you're communicating to a large audience. So that is false.
No!The internet began in the 1950s when the US government was trying to use connected computers to compete with the Soviet Union's Sputnik. Hope this helps :)
