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sergey [27]
3 years ago
15

g Given a character and a list of strings, find strings that do not contain the given character. See the example below. $ (Find

88 (list (list 77 73) (list 89))) ((77 73) (89)) $ (Find 88 (list (list 7
Computers and Technology
1 answer:
Alex_Xolod [135]3 years ago
5 0

Answer:

The solution code is written in Python 3

  1. def findStr(stringList, c):
  2.    output = []
  3.    for currentStr in stringList:
  4.        if c not in currentStr.lower():
  5.            output.append(currentStr)
  6.    return output  
  7. strList = ["Apple", "Banana", "Grape", "Orange", "Watermelon"]
  8. print(findStr(strList, "g"))

Explanation:

Firstly, we can create a function and name it as findStr which takes two input parameters stringList and a character, c (Line 1).

Create a list that will hold the list of strings that do not contain the input character (Line 2).

Create a for-loop to traverse through each string in the list (Line 3).

In the loop, check if the input character is not found in the current string (Line 4), if so, add the current string to the output list (Line 5). Please note we also need to convert the current string to lowercase as this program should ignore the casing.

After completion the loop, return the output list (Line 7).

We can test the function using a sample string list and input character "g" (Line 9 - 10). We shall get the output as follows:

['Apple', 'Banana', 'Watermelon']

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kozerog [31]

Answer:

  1. public class FindDuplicate{
  2.    public static void main(String[] args) {
  3.        Scanner input = new Scanner(System.in);
  4.        int n = 5;
  5.        int arr[] = new int[n];
  6.        for(int i=0; i < arr.length; i++){
  7.            int inputNum = input.nextInt();
  8.            if(inputNum >=1 && inputNum <=n) {
  9.                arr[i] = inputNum;
  10.            }
  11.        }
  12.        for(int j =0; j < arr.length; j++){
  13.            for(int k = 0; k < arr.length; k++){
  14.                if(j == k){
  15.                    continue;
  16.                }else{
  17.                    if(arr[j] == arr[k]){
  18.                        System.out.println("True");
  19.                        return;
  20.                    }
  21.                }
  22.            }
  23.        }
  24.        System.out.println("False");
  25.    }
  26. }

Explanation:

Firstly, create a Scanner object to get user input (Line 4).

Next, create an array with n-size (Line 7) and then create a for-loop to get user repeatedly enter an integer and assign the input value to the array (Line 9 - 14).

Next, create a double layer for-loop to check the each element in the array against the other elements to see if there is any duplication detected and display "True" (Line 21 - 22). If duplication is found the program will display True and terminate the whole program using return (Line 23). The condition set in Line 18 is to ensure the comparison is not between the same element.

If all the elements in the array are unique the if block (Line 21 - 23) won't run and it will proceed to Line 28 to display message "False".

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