<span>Simplifying
x + -1.4 = 7.82
Reorder the terms:
-1.4 + x = 7.82
Solving
-1.4 + x = 7.82
Solving for variable 'x'.
Move all terms containing x to the left, all other terms to the right.
Add '1.4' to each side of the equation.
-1.4 + 1.4 + x = 7.82 + 1.4
Combine like terms: -1.4 + 1.4 = 0.0
0.0 + x = 7.82 + 1.4
x = 7.82 + 1.4
Combine like terms: 7.82 + 1.4 = 9.22
x = 9.22
Simplifying
x = 9.22</span>
Answer:
5 yr and 39 yr
Step-by-step explanation:
Let x = the age of the younger
then 7x + 4 = the age of the older
Now x + 7x + 4 = 44
8x + 4 = 44
8x = 40
x = 5
7x + 4 = 7(5) + 4 = 35 + 4 = 39
Check: 5 + 39 = 44
To factor out completely, we should have reached the most simplified form,
first we should take out 2.
2(x2 - 3x - 18)
then we should factor out the inside of the parenthesis,
2(x - 6)(x + 3)
And that's the most simplified and factored out form.
The final answer is then the second option, <span>2(x − 6)(x + 3)</span>
<span>a.
The radius of earth is about 6400 kilometers. Find the circumference of
a great circle.
Circumference = 2π(radius) = 2π(6400 km) = 40.212,39 km
b. Write an equation for the circumference of any
latitude circle with angle theta
As stated, </span><span><span>the
length of any parallel of latitude (this is the circumference of corresponding circle) is equal to the circumference of a
great circle of Earth times the cosine of the latitude angle</span>:
=> Circumference = 2π*radius* cos(Θ) = 2 π*6400km*cos(Θ) = 40,212.39 cos(Θ)
Answer: circumference = 40,212.39 cos(Θ) km
c. Which latitude circle has a
circumference of about 3593 kilometers?
Make </span><span><span>40,212.39 cos(Θ)</span> km = 3593 km
=> cos(Θ) = 3593 / 40,212.39 = 0.08935 => Θ = arccos(0.08935) = 84.5° = 1.48 rad
Answer: 1.48
d. What is the circumference of
the Equator?
</span>
For the Equator Θ = 0°
=> circumference = 40,213.49cos(0°) km = 40,212.49 km
Answer: 40,212.49 km
Answer:
Sixth graders: 14
Seventh graders: 28
Eighth graders: 28
Step-by-step explanation:
To solve this you just have to use a rule of three to solve the percentages, remember that the 100% will be the 70 students, and we solve each case separetly:
70 students= 100%
sixth grades= 40%
Sixth grades= (40*70)/100
Sixth graders= 28
70 students= 100%
seventh grades= 20%
seventh graders= (20*70)/100
Seventh graders=14
So if we have that the rest of the students are eighth graders, we just add up the sixth and seventh graders and withdraw them from the total:
28+14=42
70-42=28
SOwe have that the eighth graders are 28
