Hello,
Here is your answer:
The proper answer to this questions is "no".
3.0 is greater than 0.3.
Your answer is no.
if you need anymore help feel free to ask me!
Hop this helps!
Step-by-step explanation:
step 1. 12x - 15 - 12x = 7x + 20
step 2. 12x - 12x - 15 = 7x + 20 (grouping of terms)
step 3. -15 = 7x + 20 (adding like terms)
step 4. -35 = 7x (subtract 20 from both sides)
step 5. this step is incorrect.
step 6. -5 = x ( divide both sides by 7)
step 7. x = -5 (put the variable first).
Answer: we dont have options
Step-by-step explanation:
||a|| is called the norm of a. The answer is square root of 58. Hope it helps
Answer:
a) P ( E | F ) = 0.54545
b) P ( E | F' ) = 0
Step-by-step explanation:
Given:
- 4 Coins are tossed
- Event E exactly 2 coins shows tail
- Event F at-least two coins show tail
Find:
- Find P ( E | F )
- Find P ( E | F prime )
Solution:
- The probability of head H and tail T = 0.5, and all events are independent
So,
P ( Exactly 2 T ) = ( TTHH ) + ( THHT ) + ( THTH ) + ( HTTH ) + ( HHTT) + ( HTHT) = 6*(1/2)^4 = 0.375
P ( At-least 2 T ) = P ( Exactly 2 T ) + P ( Exactly 3 T ) + P ( Exactly 4 T) = 0.375 + ( HTTT) + (THTT) + (TTHT) + (TTTH) + ( TTTT)
= 0.375 + 5*(1/2)^4 = 0.375 + 0.3125 = 0.6875
- The probabilities for each events are:
P ( E ) = 0.375
P ( F ) = 0.6875
- The Probability to get exactly two tails given that at-least 2 tails were achieved:
P ( E | F ) = P ( E & F ) / P ( F )
P ( E | F ) = 0.375 / 0.6875
P ( E | F ) = 0.54545
- The Probability to get exactly two tails given that less than 2 tails were achieved:
P ( E | F' ) = P ( E & F' ) / P ( F )
P ( E | F' ) = 0 / 0.6875
P ( E | F' ) = 0
