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3 years ago

Which equation can we use to find the length of the side labeled x? What is the value of x?

Mathematics

2 answers:

dexar [7]3 years ago

7 0

Answer:

D. sin 30° = 5/x

Step-by-step explanation:

recall that for a right triange, considering one of the acute angles θ

sin θ = length of opposite side / length of hypotenuse

from the picture, we can see that

θ = 30°, length of opposite site = 5 and length of hypotenuse = x

substituting this into the above equation

sin 30° = 5/x

pentagon [3]3 years ago

6 0

Answer:

option d

d ---- sin30 =5/x

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In which choice do all the points lie on the same line

Ronch [10]

Answer:

(0,0) (1,2) (2,4) (3,6)

Step-by-step explanation:

They all share the same slope which is 1/2

4 0

2 years ago

Read 2 more answers

Will give brainliest

Katen [24]

Answer:

Trapezoid

Step-by-step explanation:

The two sloped opposite sides are congruent. The two uncongruent opposite sides are parallel. There are no right angles. You can do this by finding the distance and slopes of the lines.

Not triangle because has four vertices.

3 0

2 years ago

Fill in the missing number to complete the factorization:

IrinaVladis [17]

The last terms must multiply to the last terms (confusing)

example

if ax^3+bx^2+c+d=(ex+f)(gx+h)(jx+k) then
d=fhk

so

70 is last term
we got 2 and 5
2*5*?=70
10*?=70
divide by 10
?=7

the missing number is 7

6 0

3 years ago

A survey of 76 commercial airline flights of under 2 hours resulted in a sample average late time for a flight of 2.55 minutes.

nika2105 [10]

Answer:

The best point of estimate for the true mean is:

$\hat \mu = \bar X = 2.55$

$2.55-1.96\frac{12}{\sqrt{76}}=-0.148$

$2.55+1.96\frac{12}{\sqrt{76}}=5.248$

Since the time can't be negative a good approximation for the confidence interval would be (0,5.248) minutes. The interval are tellling to us that at 95% of confidence the average late time is lower than 5.248 minutes.

Step-by-step explanation:

Information given

$\bar X=2.55$ represent the sample mean for the late time for a flight

$\mu$ population mean

$\sigma=12$ represent the population deviation

n=76 represent the sample size

Confidence interval

The best point of estimate for the true mean is:

$\hat \mu = \bar X = 2.55$

The confidence interval for the true mean is given by:

$\bar X \pm z_{\alpha/2}\frac{\sigma}{\sqrt{n}}$ (1)

The Confidence level given is 0.95 or 95%, th significance would be $\alpha=0.05$ and $\alpha/2 =0.025$ . If we look in the normal distribution a quantile that accumulates 0.025 of the area on each tail we got $z_{\alpha/2}=1.96$