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tiny-mole [99]
3 years ago
5

Hi Everyone,

Mathematics
1 answer:
CaHeK987 [17]3 years ago
5 0
A= 1/4
B=2/4
C=3/4
D=4/4=1
E=5/4
Hope I helped!
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In the book Essentials of Marketing Research, William R. Dillon, Thomas J. Madden, and Neil H. Firtle discuss a research proposa
MakcuM [25]

Answer:

Null hypothesis:p_{1} = p_{2}  

Alternative hypothesis:p_{1} \neq p_{2}  

z=\frac{0.179-0.15}{\sqrt{0.17(1-0.17)(\frac{1}{140}+\frac{1}{60})}}=0.500  

p_v =2*P(Z>0.500)=0.617  

So the p value is a very low value and using any significance level for example \alpha=0.05, 0,1,0.15 always p_v>\alpha so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can say the two proportions NOT differs significantly.  

Step-by-step explanation:

Data given and notation  

X_{1}=25 represent the number of homeowners who would buy the security system

X_{2}=9 represent the number of renters who would buy the security system

n_{1}=140 sample 1

n_{2}=60 sample 2

p_{1}=\frac{25}{140}=0.179 represent the proportion of homeowners who would buy the security system

p_{2}=\frac{9}{60}= 0.15 represent the proportion of renters who would buy the security system

z would represent the statistic (variable of interest)  

p_v represent the value for the test (variable of interest)  

Concepts and formulas to use  

We need to conduct a hypothesis in order to check if the two proportions differs , the system of hypothesis would be:  

Null hypothesis:p_{1} = p_{2}  

Alternative hypothesis:p_{1} \neq p_{2}  

We need to apply a z test to compare proportions, and the statistic is given by:  

z=\frac{p_{1}-p_{2}}{\sqrt{\hat p (1-\hat p)(\frac{1}{n_{1}}+\frac{1}{n_{2}})}}   (1)  

Where \hat p=\frac{X_{1}+X_{2}}{n_{1}+n_{2}}=\frac{25+9}{140+60}=0.17  

Calculate the statistic  

Replacing in formula (1) the values obtained we got this:  

z=\frac{0.179-0.15}{\sqrt{0.17(1-0.17)(\frac{1}{140}+\frac{1}{60})}}=0.500  

Statistical decision

For this case we don't have a significance level provided \alpha, but we can calculate the p value for this test.    

Since is a two sided test the p value would be:  

p_v =2*P(Z>0.500)=0.617  

So the p value is a very low value and using any significance level for example \alpha=0.05, 0,1,0.15 always p_v>\alpha so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can say the two proportions NOT differs significantly.  

6 0
3 years ago
Is $1.45 a natural number ,integer, irrational number, or a real number
Rainbow [258]

Answer:

Real Number  

Step-by-step explanation:

These are numbers which include both rational AND irrational!!!

Doesn't go on forever.

Brainliest??

4 0
3 years ago
Read 2 more answers
Problem 8-4 A computer time-sharing system receives teleport inquiries at an average rate of .1 per millisecond. Find the probab
Sphinxa [80]

Answer:  a) 0.9980, b) 0.0013, c) 0.0020, d) 0.00000026, e) 0.0318

Step-by-step explanation:

Problem 8-4 A computer time-sharing system receives teleport inquiries at an average rate of .1 per millisecond. Find the probabilities that the number of inquiries in a particular 50-millisecond stretch will be:

Since we have given that

\lambda=0.1\ per\ millisecond=5\ per\ 50\ millisecond=5

Using the poisson process, we get that

(a) less than or equal to 12

probability=  P(X\leq 12)=\sum _{k=0}^{12}\dfrac{e^{-5}(-5)^k}{k!}=0.9980

(b) equal to 13

probability= P(X=13)=\dfrac{e^{-5}(-5)^{13}}{13!}=0.0013

(c) greater than 12

probability= P(X>12)=\sum _{k=13}^{50}\dfrac{e^{-5}.(-5)^k}{k!}=0.0020

(d) equal to 20

probability= P(X=20)=\dfrac{e^{-5}(-5)^{20}}{20!}=0.00000026

(e) between 10 and 15, inclusively

probability=P(10\leq X\leq 15)=\sum _{k=10}^{15}\dfrac{e^{-5}(-5)^k}{k!}=0.0318

Hence, a) 0.9980, b) 0.0013, c) 0.0020, d) 0.00000026, e) 0.0318

6 0
3 years ago
The price of products may increase due to inflation and decrease due to depreciation. Derek is studying the change in the price
iren [92.7K]
Part A.

1) Function given:

f(x)=0.69(1.03)^x

2) Interpretation:

initial value: => x = 0 => f(x) = 0.69

table:

x                f(x)
year          price

0              0.69

1             0.69 * 1.03 = 0.7107 => increase = 3%

2             0.69 * (1.03)^2 = 0.732021 => increase = 3%

So, the answer is that the function is increasing at 3% per year.

Part B.

3) table

<span> t (number of years)      1             2              3                  4
f(t) (price in dollars)     10,100    10,201     10,303.01   10,406.04

Percent change:

Year 2: 10,201 / 10,100 = 1.01 => 1% increase

Year 3: 10,303.01 / 10,201 = 1.01 => 1% increase

Year 4: 10,406.04 / 10,303.01 = 1.01 => 1% increase.

Answer: the </span><span>product of the part A recorded a greater percentage change in price over the previous year (3% vs 1%).</span>
5 0
3 years ago
Given that a­­b = x, evaluate the following:<br> a^b+2
Amiraneli [1.4K]

Answer:

x^b+2/b^b+2

Step-by-step explanation:

substitute the value of the variable into the equation and simplify

6 0
3 years ago
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