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3 years ago

HELPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPP

Mathematics

2 answers:

vampirchik [111]3 years ago

8 0

Answer:

I think C

Step-by-step explanation:

rusak2 [61]3 years ago

4 0

Answer:

Each fraction of the shape is 1/3 the whole shape. So the answer is B.

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Find −2(−2.8). You may find using a number line to be helpful.

stepan [7]

Answer:

why u sooooooooooo gay

Step-by-step explanation:

3 0

3 years ago

The local radio tower is located 20 miles east and 12 miles north of Pamela's cabin. The radio tower has a 25 mile broadcast rad

pychu [463]

Answer:

x^2 +y^2 -40x -24y -81 =0

Step-by-step explanation:

We can write the equation of a circle in the form

(x-h)^2 + (y-k)^2 = r^2

Where (h,k) is the center and r is the radius

Assuming that Pamela's cabin is the center

( x-20)^2 + (y- 12)^2 = 25^2

We want to get to general form

x^2 + y^2 + Dx + Ey + F = 0,

Distributing

x^2 -40x +400 + y^2 -24y +144 = 625

x^2 +y^2 -40x -24y +544 -625 =0

x^2 +y^2 -40x -24y -81 =0

3 0

3 years ago

Mrs Hong had some milk. She used of it to bake some waffles and

Sergio [31]

Answer:

Mrs. Hong originally had 900 ml of milk

Explanation:

The complete question is in the attached image

Assume that the amount of milk Mrs. Hong originally had was x ml

We are given that:

1- She used $\frac{1}{6}$ of it to bake the waffles, therefore:

Amount used in baking waffles = $\frac{1}{6}x$ ml

2- She used 300 ml to bake a pie

3- Amount left is half the original amount, therefore:

Amount left = $\frac{1}{2}x$ ml

We know that:

Total amount = amount used in waffles + amount used in pie + amount left

Substitute with the givens and solve for x:

Total amount = amount used in waffles + amount used in pie + amount left

$x = \frac{1}{6}x + 300 + \frac{1}{2}x\\ \\x-\frac{1}{6}x-\frac{1}{2}x = 300\\ \\\frac{1}{3}x = 300\\ \\x = 300*3 = 900 ml$

This means that:

She originally had 900 ml of milk

Hope this helps :)

7 0

3 years ago

A company has net working capital of $843. Long-term debt is $4,402, total assets are $6,633, and fixed assets are $4,272. What

creativ13 [48]

Answer:

Step-by-step explanation:

6633-4272-843+4402=5920

btw,wrong subject

4 0

3 years ago

Suppose a certain population satisfies the logistic equation given by dP

Ksenya-84 [330]

Answer:

The population when t = 3 is 10.

Step-by-step explanation:

Suppose a certain population satisfies the logistic equation given by

$\frac{dP}{dt}=10P-P^2$

with P(0)=1. We need to find the population when t=3.

Using variable separable method we get

$\frac{dP}{10P-P^2}=dt$

Integrate both sides.

$\int \frac{dP}{10P-P^2}=\int dt$ .... (1)

Using partial fraction

$\frac{1}{P(10-P)}=\frac{A}{P}+\frac{B}{(10-P)}$

$A=\frac{1}{10},B=\frac{1}{10}$

Using these values the equation (1) can be written as

$\int (\frac{1}{10P}+\frac{1}{10(10-P)})dP=\int dt$

$\int \frac{dP}{10P}+\int \frac{dP}{10(10-P)}=\int dt$

On simplification we get

$\frac{1}{10}\ln P-\frac{1}{10}\ln (10-P)=t+C$

$\frac{1}{10}(\ln \frac{P}{10-P})=t+C$

We have P(0)=1

Substitute t=0 and P=1 in above equation.

$\frac{1}{10}(\ln \frac{1}{10-1})=0+C$

$\frac{1}{10}(\ln \frac{1}{9})=C$

The required equation is

$\frac{1}{10}(\ln \frac{P}{10-P})=t+\frac{1}{10}(\ln \frac{1}{9})$

Multiply both sides by 10.

$\ln \frac{P}{10-P}=10t+\ln \frac{1}{9}$

$e^{\ln \frac{P}{10-P}}=e^{10t+\ln \frac{1}{9}}$

$\frac{P}{10-P}=\frac{1}{9}e^{10t}$

Reciprocal it

$\dfrac{10-P}{P}=9e^{-10t}$

$P(t)=\dfrac{10}{1+9e^{-10t}}$

The population when t = 3 is

$P(3)=\dfrac{10}{1+9e^{-10\cdot 3}}$

Using calculator,

$P=9.999\approx 10$

Therefore, the population when t = 3 is 10.

8 0

3 years ago