Answer:
3
Step-by-step explanation:
P is the in-center
⇒PA=PE=PD because they are in-radius of the in-circle
We know that, tangent segments drawn from a point outside the circle are always equal in length
⇒DK=EK=7.2
In right triangle PKE,
using Pythagoras' Theorem : 
⇒
⇒
⇒
⇒
Therefore, 
For the second question, your first option is correct, you would rewrite 8 in power-base form 8=2^3 as the first step to solving the equation, power base form is exponential form.
27, 36, 45...all have factors of 9 and r greater then 20
if a plane flies 455 miles with wind, and takes 400 against the wind, and the wind is blowing at a speed of 12mph, then the plane can fly 2455 miles if it's still in the air
If the points are
collinear, then that would mean that the points lie on the same line when joined
to each other. In order to confirm this, the distances between the points must
sum up to the length of the line.<span>
AB + BC = AC
7 + 4 ? 9
11 ≠ 9
<span>Since they do not sum up, therefore, the points are not
collinear.</span></span>