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polet [3.4K]
2 years ago
15

Which of the following is a factor of (x+y)³-(x+y)³

Mathematics
2 answers:
IgorC [24]2 years ago
6 0

▬▬▬▬▬▬▬▬▬▬▬▬▬▬

<h3>Answer :</h3>

The factor of (x + y)³- (x³ + y³) is <u>3xy</u>

<h3>Step By Step Solution :</h3>

→ (x + y)³- (x³ + y³)

→ (x + y) - (x + y)(x² - xy + y²) [Using identity a³ + b³ = (a + b)(a²- ab+ b²)]

→ (x + y)(x² + y² + 2xy - x² + xy - y²)[Using identity, (a + b)² = (a² + b²+ 2ab)]

→ (x + y) (3xy)

→ 3xy

∴ Option d. 3xy is correct!

▬▬▬▬▬▬▬▬▬▬▬▬▬▬

EleoNora [17]2 years ago
5 0

Answer:

(x+y)³= x³+y³+3xy(x+y)

x³+y³+3xy(x+y) - x³-y³

x³ and y³ gets cancelled out, and we are left with

3xy(x+y)

so, we have 3xy as one of our factors.

hope it helps!

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2 years ago
A number is 6 less than its square. find all such numbers?
cestrela7 [59]
Hello There!

2² - 6 = -2
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3 0
3 years ago
Read 2 more answers
Hey, I need help BAD!! I am doing PEMDAS. 7+(5times6)45+9<br><br><br> Please help me!! Thanks!
leonid [27]

Answer:1

<h2>1,366</h2>

Step-by-step explanation:

P - parenthsis

E - exponents

M - multiplication

D - division

A - addition

S - subtraction

<h3>STICK TO THE ORDER:</h3>

7 + 5 x (6 x 45) + 9 = 1,336 ( Not the pemdas order)

But,

<h3>7 + (5 x 6)45 + 9 = 1,366  is the correct order for using PEMDAS.</h3>
4 0
3 years ago
If every student in a large Statistics class selects peanut M&amp;M’s at random until they get a red candy, on average how many
kotykmax [81]

Question:

According to Masterfoods, the company that manufactures M&M's, 12% of peanut M&M's are brown, 15% are yellow, 12% are red, 23% are blue, 23% are orange and 15% are green. You randomly select peanut M&M's from an extra-large bag looking for a red candy.

If every student in a large Statistics class selects peanut M&M’s at random until they get a red candy, on average how many M&M’s will the students need to select? (Round your answer to two decimal places.).

Answer:

If every student in the large Statistics class selects peanut M&M’s at random until they get a red candy the expected value of the number of  M&M’s the students need to select is 8.33 M&M's.

Step-by-step explanation:

To solve the question, we note that the statistical data presents a geometric mean. That is the probability of success is of the form.

The amount of repeated Bernoulli trials required before n eventual success outcome or

The probability of having a given number of failures before the first success is recorded.

In geometric distribution, the probability of having an eventual successful outcome depends on the the completion of a certain number of attempts with each having the same probability of success.

If the probability of each of the preceding trials is p and the kth trial is the  first successful trial, then the probability of having k is given by

Pr(X=k) = (1-p)^{k-1}p  

The number of expected independent trials to arrive at the first success for a variable Xis 1/p where p is the expected success of each trial hence p is the probability for the red and the expected value of the number of trials is 1/p or where p = 12 % which is 0.12

1/p = 1/0.12 or 25/3 or 8.33.

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8 0
3 years ago
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