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lianna [129]
3 years ago
14

Your business makes custom baby quilts. You plan to sell your quilts online and have a choice of two web companies that you can

sell your quilts through. Company A charges an online store fee of $75 per month plus 10% of your sales. Company B charges you 12% of your sales but no monthly fee.If you sold $3,750 per month, which company would be the best deal?
Mathematics
2 answers:
sattari [20]3 years ago
7 0
Company b  because you dont need to give them 75 per month you would just need to give to more percent
lapo4ka [179]3 years ago
6 0
They both come out to 450 a month. The answer would be that they are both a good deal. Explanation for A, 3750x.10 would give you 375 then add 75 and get 450. Then for Answer B you would multiply 3750 by .12 and get 450. Dont know if this helps or is the answer but hopefully it is right.
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Expand the given power using the Binomial Theorem. (10k – m)5
agasfer [191]

Answer:

(10k - m)^{5}=100000k-50000k^{4}m+10000k^{3}m^{2}-1000k^{2}m^{3}+50km^{4}-m^{5}

Step-by-step explanation:

* Lets explain how to solve the problem

- The rule of expand the binomial is:

(a+b)^{n}=(a)^{n}+nC1(a)^{n-1}(b)+nC2(a)^{n-2}(b)^{2}+nC3(a)^{n-3}(b)^{3}+...............+(b)^{5}

∵ The binomial is (10k-m)^{5}

∴ a = 10k , b = -m and n = 5

∴ (10k-m)^{5}=(10k)^{5}+5C1(10k)^{4}(-m)+5C2(10k)^{3}(-m)^{2}+5C3(10k)^{2}(-m)^{3}+5C4(10k)^{1} (-m)^{4}+5C5(10k)^{0}(-m)^{5}

∵ 5C1 = 5

∵ 5C2 = 10

∵ 5C3 = 10

∵ 5C4 = 5

∵ 5C5 = 1

∴ (10k-m)^{5}=100000k^{5}+(5)(10000)k^{4}(-m)+(10)(1000)k^{3}(m^{2})+(10)(100)k^{2}(-m^{3})+5(10k)^{1} (m^{4})+(10k)^{0}(-m^{5})

∴ (10k-m)^{5}=100000k^{5}-50000)k^{4}m+10000k^{3}m^{2}-1000k^{2}m^{3}+50km^{4}-m^{5}

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3 years ago
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