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Genrish500 [490]
3 years ago
7

Please help me with this

Mathematics
1 answer:
cupoosta [38]3 years ago
5 0
Can you please write what the question is? I need to know what the category is to figure out which one does not belong.
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D/5 = 4 please explain I do not get this. Thank you
MAXImum [283]
<span>D/5 = 4
Multiply 5 on both sides
Final Answer: D = 20</span>
8 0
3 years ago
There are 12 inches in one foot, creating the equation y=12x If a door frame is 5.75 feet tall, how many inches tall is it?
Neko [114]
There are 69 inches in 5.75 feet.
8 0
3 years ago
Can someone please help?
goldfiish [28.3K]

Answer:

a.   max. 25c. min.13c

b.  2:00

Step-by-step explanation:

6 0
3 years ago
Consider a rabbit population​ P(t) satisfying the logistic equation StartFraction dP Over dt EndFraction equals aP minus bP squa
maria [59]

Solution:

Given :

$\frac{dP}{dt}= aP-bP^2$         .............(1)

where, B = aP = birth rate

            D = $bP^2$  =  death rate

Now initial population at t = 0, we have

$P_0$ = 220 ,  $B_0$ = 9 ,  $D_0$ = 15

Now equation (1) can be written as :

$ \frac{dP}{dt}=P(a-bP)$

$\frac{dP}{dt}=bP(\frac{a}{b}-P)$    .................(2)

Now this equation is similar to the logistic differential equation which is ,

$\frac{dP}{dt}=kP(M-P)$

where M = limiting population / carrying capacity

This gives us M = a/b

Now we can find the value of a and b at t=0 and substitute for M

$a_0=\frac{B_0}{P_0}$    and     $b_0=\frac{D_0}{P_0^2}$

So, $M=\frac{B_0P_0}{D_0}$

          = $\frac{9 \times 220}{15}$

          = 132

Now from equation (2), we get the constants

k = b = $\frac{D_0}{P_0^2} = \frac{15}{220^2}$

        = $\frac{3}{9680}$

The population P(t) from logistic equation is calculated by :

$P(t)= \frac{MP_0}{P_0+(M-P_0)e^{-kMt}}$

$P(t)= \frac{132 \times 220}{220+(132-220)e^{-\frac{3}{9680} \times132t}}$

$P(t)= \frac{29040}{220-88e^{-\frac{396}{9680} t}}$

As per question, P(t) = 110% of M

$\frac{110}{100} \times 132= \frac{29040}{220-88e^{\frac{-396}{9680} t}}$

$ 220-88e^{\frac{-99}{2420} t}=200$

$ e^{\frac{-99}{2420} t}=\frac{5}{22}$

Now taking natural logs on both the sides we get

t = 36.216

Number of months = 36.216

8 0
4 years ago
Solve the following inequality.
user100 [1]

Answer:

A

Step-by-step explanation:

Given

21 ≤ - 3(x - 4) < 30 ← divide all 3 intervals by - 3

Remembering to reverse the direction of the signs as a result of dividing by a negative quantity

- 7 ≥ x - 4 > - 10 ← add 4 to each interval

- 3 ≥ x > - 6, that is

- 6 < x ≤ - 3 → A

5 0
3 years ago
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