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Misha Larkins [42]

3 years ago

11

How much compound interest will $50,000 earn in 10 years at 3.4% APR compounded yearly, providing no deposits or withdrawals are

made? Hint: Use the formula A = P(1.00 + r)n.
$19,851.44
$63,970.00
$13,970.29
$69,851.44

1 answer:

Otrada [13]3 years ago

7 0

Answer:

$19,851.44

Step-by-step explanation:

A = 50,000(1.00 + 0.034)^10

= $69,851.44

= 69,851.44 - 50,000

= $19,851.44

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Step-by-step explanation:

Given lines : y = √x, y = 2, x = 0.

<u>a) The x-axis </u>

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y = √x = , x = y^2

h = y^2 , p = y

vol = ( 2π ) $\int\limits^2_0 {ph} \, dy$

= $( 2\pi ) \int\limits^2_0 {y.y^2} \, dy$

∴ Vol = 8π

<u>b) The line y = 2 ( using the shell method )</u>

p = 2 - y

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vol = ( 2π ) $\int\limits^2_0 {ph} \, dy$

= $( 2\pi ) \int\limits^2_0 {(2-y).y^2} \, dy$

= ( 2π ) * [ 2/3 * y^3 - y^4 / 4 ] ²₀

∴ Vol = 8/3 π

<u>c) The y-axis ( using shell method )</u>

h = 2-y = h = 2 - √x

p = x

vol = $(2\pi ) \int\limits^4_0 {ph} \, dx$

= $(2\pi ) \int\limits^4_0 {x(2-\sqrt{x} ) } \, dx$

= ( 2π ) [x^2 - 2/5*x^5/2 ]⁴₀

vol = ( 2π ) ( 16/5 ) = 32/5 π

<u>d) The line x = -1 (using shell method )</u>

p = 1 + x

h = 2√x

vol = $(2\pi ) \int\limits^4_0 {ph} \, dx$

Hence vol = 176/15 π

attached below is the graphical representation of P and h

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