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maw [93]
3 years ago
11

What is the slope of a line with the equation y=5x+2/5

Mathematics
1 answer:
igomit [66]3 years ago
4 0
The slope-intercept form: y = mx + b

m - a slope

y = 5x + 2/5

Answer: The slope m = 5.
You might be interested in
Main Idea: To evaluate an exponential growth or decay function, substitute a value for the exponent variable and simplify.
Helen [10]
If there is more to the answer than what I give please ask for more!

With F(x) = 3^{x} we can find F(4) by substituting 4 into the main function.

So it would look like this: F(4) = 3^{4} = 3*3*3*3 = 81

Hope this helps!
3 0
3 years ago
the height h(t) of a trianle is increasing at 2.5 cm/min, while it's area A(t) is also increasing at 4.7 cm2/min. at what rate i
nekit [7.7K]

Answer:

The base of the triangle decreases at a rate of 2.262 centimeters per minute.

Step-by-step explanation:

From Geometry we understand that area of triangle is determined by the following expression:

A = \frac{1}{2}\cdot b\cdot h (Eq. 1)

Where:

A - Area of the triangle, measured in square centimeters.

b - Base of the triangle, measured in centimeters.

h - Height of the triangle, measured in centimeters.

By Differential Calculus we deduce an expression for the rate of change of the area in time:

\frac{dA}{dt} = \frac{1}{2}\cdot \frac{db}{dt}\cdot h + \frac{1}{2}\cdot b \cdot \frac{dh}{dt} (Eq. 2)

Where:

\frac{dA}{dt} - Rate of change of area in time, measured in square centimeters per minute.

\frac{db}{dt} - Rate of change of base in time, measured in centimeters per minute.

\frac{dh}{dt} - Rate of change of height in time, measured in centimeters per minute.

Now we clear the rate of change of base in time within (Eq, 2):

\frac{1}{2}\cdot\frac{db}{dt}\cdot h =  \frac{dA}{dt}-\frac{1}{2}\cdot b\cdot \frac{dh}{dt}

\frac{db}{dt} = \frac{2}{h}\cdot \frac{dA}{dt} -\frac{b}{h}\cdot \frac{dh}{dt} (Eq. 3)

The base of the triangle can be found clearing respective variable within (Eq. 1):

b = \frac{2\cdot A}{h}

If we know that A = 130\,cm^{2}, h = 15\,cm, \frac{dh}{dt} = 2.5\,\frac{cm}{min} and \frac{dA}{dt} = 4.7\,\frac{cm^{2}}{min}, the rate of change of the base of the triangle in time is:

b = \frac{2\cdot (130\,cm^{2})}{15\,cm}

b = 17.333\,cm

\frac{db}{dt} = \left(\frac{2}{15\,cm}\right)\cdot \left(4.7\,\frac{cm^{2}}{min} \right) -\left(\frac{17.333\,cm}{15\,cm} \right)\cdot \left(2.5\,\frac{cm}{min} \right)

\frac{db}{dt} = -2.262\,\frac{cm}{min}

The base of the triangle decreases at a rate of 2.262 centimeters per minute.

6 0
3 years ago
The temperature in the morning is 18.6°C. By noon the temperature rises 8.5°C.
Harman [31]

Answer:

27.1°C

Step-by-step explanation:

7 0
3 years ago
Find a compatible dividend for the division problem.<br><br> 492 divided 87<br> ? Divided 90
jeyben [28]

Answer:

0.0628352490421456‬ or 0.1

Step-by-step explanation:

Step by step solution :

Step  1  :

           164

Simplify   ———

           29  

Equation at the end of step  1  :

 164

 ——— ÷ 90

 29  

Step  2  :

        164      

Divide  ———  by  90

        29        

Final result :

  82            

 ———— = 0.06284  

 1305          

7 0
3 years ago
What is the solution (a, c) to this system of linear equations?
Akimi4 [234]
Method:

Simultaneous equations

Explanation:

First we will need to get both equations to have the same subject, to do this we will multiply the bottom equation by 2.

1) 2a-3c=-6

2) a+2c=11 x2
Becomes
2) 2a+4c=22

Now we will make both equations equal to the same subject (2a)

1) 2a=3c-6
2) 2a=-4c+22

Because they are both equal to 2a, they are therefore equal to each other, so:

3c-6=-4c+22
7c=28
c=4

Now substitute c back into either equation to get a:

a+2c=11
a+2(4)=11
a=3
3 0
4 years ago
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