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3 years ago

Solve this equation: 2cosx+5=4

Mathematics

2 answers:

erma4kov [3.2K]3 years ago

8 0

$\frac{2 \pi }{3}$

tangare [24]3 years ago

5 0

Answer:

2pi/3 and 4pi/3

Step-by-step explanation:

Solve for cosine and you will get cosx=-1/2. Using the unit circle find every point where the x value = -1/2 (since cosine is x). You will find that the angles where x = -1/2 are 2pi/3 and 4pi/3

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Select the correct answer.

lions [1.4K]

Answer:

the answer is C - no association

7 0

2 years ago

Read 2 more answers

Substitution for {2x-3y=11 and -x + 2y = -6

Svetradugi [14.3K]

Step-by-step explanation:

-x+2y=-6

x-2y=6

x=2y+6

substitute in 2x-3y=11 gives us 2(2y+6)-3y=11

4y+12-3y=11

y=-1

-x+2(-1)=-6

-x=-4

x=4

7 0

3 years ago

Eric's class consists of 12 males and 16 females. If 3 students are selected at random, find the probability that they

Reptile [31]

Answer:

The probability that all are male of choosing '3' students

P(E) = 0.067 = 6.71%

Step-by-step explanation:

Let 'M' be the event of selecting males n(M) = 12

Number of ways of choosing 3 students From all males and females

$n(M) = 28C_{3} = \frac{28!}{(28-3)!3!} =\frac{28 X 27 X 26}{3 X 2 X 1 } = 3,276$

Number of ways of choosing 3 students From all males

$n(M) = 12C_{3} = \frac{12!}{(12-3)!3!} =\frac{12 X 11 X 10}{3 X 2 X 1 } =220$

The probability that all are male of choosing '3' students

$P(E) = \frac{n(M)}{n(S)} = \frac{12 C_{3} }{28 C_{3} }$

$P(E) = \frac{12 C_{3} }{28 C_{3} } = \frac{220}{3276}$

P(E) = 0.067 = 6.71%

Final answer:-

The probability that all are male of choosing '3' students

P(E) = 0.067 = 6.71%

3 0

3 years ago

3 packs of soda cost $10 less than 5 packs of soda. Write and equation that models this, and solve.

zysi [14]

Cost 1 pack = x
3x + 10 = 5x
2x = 10
x = 5
1 pack cost $5
Hope this helped

8 0

3 years ago

Elenna [48]

If you use the scientific notation to simplify these bigger numbers it will make it easier

7 0

3 years ago