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spayn [35]
2 years ago
15

Find the common difference for the sequence shown: [1/5, 13/40, 9/20...)

Mathematics
1 answer:
bazaltina [42]2 years ago
6 0
<h3>Answer:  1/8</h3>

Explanation:

Pick any term and subtract off the previous term to get the common difference.

So,

13/40 - 1/5 = 13/40 - 8/40 = (13-8)/40 = 5/40 = 1/8

Or

9/20 - 13/40 = 18/40 - 13/40 = (18-13)/40 = 5/40 = 1/8

The positive common difference value indicates this arithmetic sequence is increasing.

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Solve : 4(4p+6)=16 find the value of p
inna [77]

Answer:

p=-1/2

Step-by-step explanation:

4(4p+6)=16

4p+6=4

4p=4-6

4p=-2

P=-2/4

p=-1/2

7 0
3 years ago
Ray Cupple bought a basic car costing $26,500.00, with options costing $725.00. There is a 6% sales tax in his state and a combi
Alenkinab [10]
Given:
cost:                        26,500
option:                  <u>        725</u>
total                         27,225
tax  (27,225 * 6%)<u>     1,633.50</u>
total                         28,858.50
license & reg. fee <u>          50.00</u>
total cost               28,908.50  Choice D.

5 0
3 years ago
Read 2 more answers
I really need an answer as soon as possible. 10 pts worth it
viva [34]

Answer:

A. Correct: When we plug in g(x) for the x in f(x), we get H(x).

B. Correct: When we plug in g(x) for the x in f(x), we get H(x).

C. Correct: When we plug in g(x) for the x in f(x), we get H(x).

D. Correct: When we plug in g(x) for the x in f(x), we get H(x).

Step-by-step explanation:

<em>Brainliest, please!</em>

8 0
3 years ago
The sum of the squares of two consecutive positive integers is 41. Find the two
Komok [63]

We have to present the number 41 as the sum of two squares of consecutive positive integers.

1² = 1

2² = 4

3² = 9

4² = 16

5² = 25

16 + 25 = 41

<h3>Answer: 4 and 5</h3>

Other method:

n, n + 1 - two consecutive positive integers

The equation:

n² + (n + 1)² = 41     <em>use (a + b)² = a² + 2ab + b²</em>

n² + n² + 2(n)(1) + 1² = 41

2n² + 2n + 1 = 41     <em>subtract 41 from both sides</em>

2n² + 2n - 40 = 0     <em>divide both sides by 2</em>

n² + n - 20 = 0

n² + 5n - 4n - 20= 0

n(n + 5) - 4(n + 5) = 0

(n + 5)(n - 4) = 0 ↔ n + 5 = 0 ∨ n - 4 =0

n = -5 < 0 ∨ n = 4 >0

n = 4

n + 1 = 4 + 1 = 5

<h3>Answer: 4 and 5.</h3>
7 0
3 years ago
58. Graph the function y=x^2+3x-18. How many real roots does the function have?
Airida [17]

9514 1404 393

Answer:

  58. 2 real roots; see attached for a graph

  59. -6, 3

Step-by-step explanation:

58. A graphing calculator graphs this easily. The graph is shown in the attachment. There are 2 x-intercepts, hence 2 real roots.

__

59. The x-intercepts are (-6, 0) and (3, 0), so the x-values x=-6 and x=3 satisfy the equation y = 0.

8 0
3 years ago
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