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3 years ago

Using elimination process what is the answer for 14x+2y=18 -7x-4=9 use steps

1 answer:

8 0

Step 1; multiple equation 2 by -2: 14x+8y=-18
step2: subtract this new equation from equation 1 to eliminate x:
2y-8y=18-(-18)
-6y=36
y=-6
step 3: substitute y=6 in equation 2: -7x-4*(-6)=9, -7x=-15, x=15/7

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Solve 5y - 2 = 3y + 14

Valentin [98]

Answer: y=8

Step-by-step explanation:

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3 years ago

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What is the answer (-32)^-3/5

horsena [70]

$-32 ^{- \frac{3}{5} }$

$\frac{1}{-32}^{ \frac{3}{5} }$

$= \sqrt[5]{ (\frac{1}{-32}) ^{3} }$

$=- \frac{1}{8}$

Answer: $- \frac{1}{8}$

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3 years ago

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Please help i need this

Svet_ta [14]

Slope Formula - (y² - y¹) / (x² - x¹)

(1, 7)

x¹ = 1

y¹ = 7

(-4, -8)

x² = -4

y² = -8

-8 - 7 = -15

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-15/5 = -3

Your answer is -3.

Hope this Helps!!

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3 years ago

Heyy can you please help me posted picture of question

vichka [17]

We can use quadratic formula to determine the roots of the given quadratic equation.

The quadratic formula is:

$x= \frac{-b+- \sqrt{ b^{2} -4ac} }{2a}$

b = coefficient of x term = 4
a = coefficient of squared term = 1
c = constant term = 7

Using the values, we get:

$x= \frac{-4+- \sqrt{16-4(1)(7)} }{2(1)} \\ \\ 
x= \frac{-4+- \sqrt{-12} }{2} \\ \\ 
x= \frac{-4+-2 \sqrt{-3} }{2} \\ \\ 
x= -2+- \sqrt{-3}$

So, the correct answer to this question is option A

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3 years ago

If x and y are both negative when is x-y positive

Vladimir [108]

X-y is positive when y is further away from 0, compared to x. In other words, when y is a larger negative

For example
x = -2
y = -5

x-y = -2-(-5) = -2+5 = 3

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3 years ago