$\log_{4}(x+10)+\log_{4}(x-2)=\log_{4}(64)\\\\\log_{4}\left((x+10)(x-2)\right)=\log_{4}(64)\\\\(x+10)(x-2)=64\\\\x^2-2x+10x-20=64\\\\x^2-2x+10x-20-64=0\\\\$

$x^2+8x-84=0\\\\(x+14)(x-6)=0\\\\x+14=0 \ \text{ or } \ x-6=0\\\\x=-14 \ \text{ or } \ x=6\\\\$

Those are the possible solutions, but plugging x = -14 back into the original equation will lead to an error. So we rule x = -14 out

x = 6 works as a solution however

3 0

3 years ago

NEED HELP FAST!

mihalych1998 [28]

The answer is currently A so yep thats the answer ok

8 0

2 years ago

Read 2 more answers

How much will the taxi driver earn if he takes one passenger 4.8 miles in another passenger 7.3 miles explain your process

Tcecarenko [31]

Answer:

12.1x+t

Step-by-step explanation:

since we do not get a specific amount we must add 4.8 and 7.3 and substitute the amount the driver earns per mile with x and use t as a variable if they charge something like $5 just to get in before driving

6 0

2 years ago

What's the distance between (-5,-6) and (4,2)

Andreyy89

The negitives are far from the 0 so its less than the non negitives

5 0

3 years ago