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3 years ago

The computer won’t accept my answers and my teacher doesn’t accept late work

Mathematics

1 answer:

LiRa [457]3 years ago

7 0

Email the teacher and see if she can check it at a later time

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URGENT PLEASE HELP ME ON THIS QUESTION.!!! the first term of a sequence of numbers is 18

Fynjy0 [20]

Well this problem can be solved with Algebra

the rule here is that for every incrementing sequence you increase your number by 6.

T(n)=18+6(n-1)

for 603 to be in the sequence, it has to male sense with the function above

603=18+6(n-1)

603-18=585

585=6(n-1)

n-1=(585/6)

n=(585+6)/6

n=591/6

here is your answer.

3 0

3 years ago

Help me with the question of O.math

Mashutka [201]

Answer:

Step-by-step explanation:

2*1+1+2*2+1+2*3+1+2*4+1=24

6 0

2 years ago

Li mixes 3 liters of red paint with 8 liters of white paint to get pink. How many units of red paint should she mix with 24 lite

professor190 [17]

Would it be 9 because 8 times 3 equals 24 and 3 times 3 equals 9

6 0

3 years ago

1. Sally said that when you add or subtract positive or negative decimals, you can change the order of the decimals and still ge

siniylev [52]

Always true because addition and subtraction is commutative
-6.2-(-3.96) = -2.24
-3.96-(-6.2)= -2.24
5.71+2.84=8.55
2.84+5.71=8.55
Hope this helped :)

3 0

3 years ago

A projectile is launched into the air. The function h(t) = –16t2 + 32t + 128 gives the height, h, in feet, of the projectile t s

Zinaida [17]

Answer:

t = 4 seconds

Step-by-step explanation:

The height of the projectile after it is launched is given by the function :

$h(t)=-16t^2+32t+128$

t is time in seconds

We need to find after how many seconds will the projectile land back on the ground. When it land, h(t)=0

So,

$-16t^2+32t+128=0$

The above is a quadratic equation. It can be solved by the formula as follows :

$t=\dfrac{-b\pm \sqrt{b^2-4ac} }{2a}$

Here, a = -16, b = 32 and c = 128

$t=\dfrac{-32\pm \sqrt{(32)^2-4\times (-16)(128)} }{2\times (-16)}\\\\t=\dfrac{-32+ \sqrt{(32)^2-4\times (-16)(128)} }{2\times (-16)}, \dfrac{-32\- \sqrt{(32)^2-4\times (-16)(128)} }{2\times (-16)}\\\\t=-2\ s\ \text{and}\ 4\ s$

Neglecting negative value, the projectile will land after 4 seconds.

4 0

3 years ago