Answer:
y = 2x + 15 OR 2x- y +15 =0
Step-by-step explanation:
To find the equation for the line parallel to the line -8x + 4y = 4, passing through the point (-6,3), we will first make the equation given to be in slope-intercept form, so that we can find the slope of this line
-8x + 4y = 4 we have to change it to the form y=mx + c
To do that, lets add 8x to both-side of the equation
8x -8x +4y=8x+4
4y=8x+4
divide both-side of the equation by 4
4y/4 = 8x/4 +4/4
y=2x + 1
comparing the above equation with y=mx + c
our slope(m) = 2
Any equation parallel to this line will have the same slope, so the slope(m) of our new equation will also be 2
Now we need to find the intercept of our new equation, to do that we will plug in the points given and our new slope into y=mx + c and find the value of our intercept(c)
The points given are x=-6 and y=3 and our new slope is m=2
plugging in our variables, thus;
y =mx + c
3 = 2(-6) + c
3 = -12 + c
add 12 to both-side of the equation
3+12 = -12+12+c
15=c
c=15
Therefore our intercept for the new equation is 15
To form our new equation, we will just plug in our new slope and intercept into y=mx + c
y = 2x + 15 (this is in slope intercept form)
we can rearrange it to be in standard form;
2x- y-15=0
