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Trava [24]
3 years ago
11

Solve

tle=" \sqrt{3} = \frac{h}{h - 3000} " alt=" \sqrt{3} = \frac{h}{h - 3000} " align="absmiddle" class="latex-formula">

Please, step by step
Mathematics
1 answer:
dezoksy [38]3 years ago
8 0
<span>\sqrt{3}(h-3000)=h
</span>(\sqrt{3}h-\sqrt{3}(3000)=h
(\sqrt{3}-1)h=\sqrt{3}(3000)
h=\frac{\sqrt{3}(3000)}{(\sqrt{3}-1)}
=\frac{\sqrt{3}(3000)}{(\sqrt{3}-1)}
=7098.076 (approximately)
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Gemiola [76]

a) The solution for the equation 2x + 16 = 5x + 4  is x=4.

b) The solution for the equation 3x − 5 = 2x + 14 is x=19.

c) The solution for the equation 5x − 5 = x + 15 is x=5.

<u>Step-by-step explanation:</u>

<u>a) The given equation is  2x + 16 = 5x + 4 </u>

  • From the above equation, it can be found that the equation consists of x terms and constant terms.
  • Therefore, bring all the x terms on one side and the constant terms on other side of the equation.
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⇒ 16-4 = 5x-2x

⇒ 12 = 3x

⇒ x = 12/3

⇒ x = 4

The solution for the given equation is x=4.

<u>To check, substitute x=4 in the equation :</u>

2(4) + 16 = 5(4) + 4

8+16 = 20+4

24 = 24

Therefore, the solution x=4 satisfies the equation 2x + 16 = 5x + 4

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<u>b) The given equation is 3x − 5 = 2x + 14</u>

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The solution for the given equation is x=19.

<u>To check, substitute x=19 in the equation :</u>

3(19) - 5 = 2(19) + 14

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Therefore, the solution x=19 satisfies the equation 3x − 5 = 2x + 14

Similarly,

<u>c) The given equation is 5x − 5 = x + 15</u>

⇒ 5x-x = 15+5

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⇒ x = 20/4

⇒ x = 5

The solution for the given equation is x=5.

<u>To check, substitute x=5 in the equation :</u>

5(5) - 5 = 5 + 15

25-5 = 20

20 = 20

Therefore, the solution x=5 satisfies the equation 5x − 5 = x + 15

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Answer:

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Step-by-step explanation:

we are asked to subtract 7x-9 from 2x^2-11

so, 2x^2-11-(7x-9)\\=2x^2-11-7x+9\\=2x^2-7x-2.

Hence the desired result is:  2x^2-7x-2.


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