Question

A plane flies along a straight line path after taking off, and it ends up 210 km farther east and 90.0 km farther north, relative to where it started. What is the plane's displacement?

Answer 1

A plane flies along a straight line path after taking off, and it ends up 210 km farther east and 90.0 km farther north, relative to where it started. we should use Pythagoras theorem for this. distance^2= 210^2 + 90^2.=228.47km, when rounding off this would comes around 230 km

Answer 2

Answer:

The plane's displacement is 228.47 km.

Explanation:

It is given that,

Distance covered in east direction is 210 km and distance covered in north direction is 90 km. Let d is the plane's displacement. It is equal to the shortest path covered by the particle.

$d=\sqrt{d_1^2+d_2^2}$

$d=\sqrt{(210)^2+(90)^2}$

d = 228.47 km

So, the plane's displacement is 228.47 km. Hence, this is the required solution.