The planets have (their) moons. So the answer would be planets.
The answer to your question is metaphase
Answer:
We know that for a pendulum of length L, the period (time for a complete swing) is defined as:
T = 2*pi*√(L/g)
where:
pi = 3.14
L = length of the pendulum
g = gravitational acceleration = 9.8 m/s^2
Now, we can think on the swing as a pendulum, where the child is the mass of the pendulum.
Then the period is independent of:
The mass of the child
The initial angle
Where the restriction of not swing to high is because this model works for small angles, and when the swing is to high the problem becomes more complex.
23 m/s (dividing by 1000 m/km) = 0.023 km/sDistance (3 km) divided by Speed (0.023 km/s) gives us Time = 130.43478... secSo it takes the first car mentioned about 130 seconds to move from the entrance ramp to the next exit.
We would like the second car to cover the same distance in the same time, but not be traveling at a steady pace, instead start at 0 and constantly increase speed. Even though the speed will be changing each instant, the AVERAGE speed of the second car will be the same as the speed of the first car over those 3 km in order for them to meet again. So the average speed of the second car will be 23 m/s.
Acceleration is a rate of change of speed, (or average speed divided by time). So, to find the acceleration of the second car, we divide 23 m/s by the time 130.43... s. This yields 0.17633333... m/s^2 as the acceleration needed."
