3 years ago

Question 5 of 5 Triangle ABC is an equilateral triangle. How many lines of symmetry does triangle ABC have?

Mathematics

1 answer:

lutik1710 [3]3 years ago

4 0

I believe just 1 because an equilateral triangle can only be reflected on one line for the halves to be the same

You might be interested in

Point C is located at (1, 2) and point D is located at (-4, -2). Find the X value for the point that is 1/4 the distance from po

kolbaska11 [484]

D (-4; -2)
C (1; 2)
M (x; y)
DM+MC=CD
CM:MD=1:3
M: x= x(C)-(x(C) - x(D))/4=1-(1-(-4))/4=1 - (6/4)=1 - 1,5= - 0,5
M: y=y(C)-(y(C) - y(D))/4=2-(2-(-2))/4=2 - (4/4)=2 - 1=1
M(x; y)=M( -0,5; 1)

8 0

4 years ago

One million people have equal chances of being called by telephone from a broadcasting show. Determine the probability of one pa

Alekssandra [29.7K]

One of one million people.

8 0

3 years ago

Read 2 more answers

Write the quadratic equation whose roots are -6 and 6, and whose leading coefficient is 1 .

SCORPION-xisa [38]

Answer:

The quadratic equation is: $y=x^2-36$

Step-by-step explanation:

If the roots of the quadratic equation are "-6" and "6", then it must have the following factors: $(x+6)\,\, and \,\,(x-6)$

Therefore, we can write the equation in factor form as:

$y=a\,(x+6)\,(x-6)$

where a is a real number constant factor. Now, this equation in standard form will look like:

$y=a\,(x^2+6x-6x-6^2)=a\,(x^2-36)=ax^2-36\,a$

Therefore, using the information about the leading coefficient being "1" (one), we derive that the constant factor $a$ must be "1". The final expression for the quadratic becomes: