Answer:
(115.2642, 222.7358).
Step-by-step explanation:
Given data:
type A: n_1=60, xbar_1=1827, s_1=168
type B: n_2=180, xbar_2=1658, s_2=225
n_1 = sample size 1, n_2= sample size 2
xbar_1, xbar_2 are mean life of sample 1 and 2 respectively. Similarly, s_1 and s_2 are standard deviation of 1,2.
a=0.05, |Z(0.025)|=1.96 (from the standard normal table)
So 95% CI is
(xbar_1 -xbar_2) ± Z×√[s1^2/n1 + s2^2/n2]
=(1827-1658) ± 1.96×sqrt(168^2/60 + 225^2/180)
= (115.2642, 222.7358).
Answer:
<h2>Sorry mate I am not able to understand ur question ❓❓❓❓ . sorry mate next time I can give u the answer.</h2>
Answer:
PQ = 3.58, and RQ = 10.4
Step-by-step explanation:
We are given the hypotenuse of the triangle, and an angle. Use sin and cos to solve.
Hypotenuse = 11,
Opposite side is PQ
Adjacent side is RQ
x = 19
Sin x = (opposite side)/(hypotenuse)
Cos x = (adjacent side)/(hypotenuse)
For PQ, this is the side opposite to the angle, so use sin,
Sin 19 = x/11
11(Sin 19) = x
3.58 = x (rounded to the nearest hundredth)
For RQ, this is the side adjacent to the angle, so use cos,
Cos 19 = x/11
11(Cos 19) = x
10.4 = x (rounded to the nearest hundredth)
Answer:
21
Step-by-step explanation:
because you rupedid lol
Well since two solid numbers cant make 7 I would do 3.5 x 7
