Answer:
1 in 16
Explanation:
When two heterozygotes (AaBb x AaBb) for two autosomal genes are crossed the expected probability for the offspring is 9 A-B-, 3 A-bb, 3 aaB- and 1 aabb. In other words, out of sixteen offspring, 9 are expected to be dominant on both genes (either homozygous AA or BB or heterozygous Aa or Bb), 3 are expected to be dominant on the A gene but recessive on the b gene, 3 are expected to be recessive on the a gene but dominant on the A gene, and only 1 is expected to be recessive on both genes aabb.
Answer:
b. Facial nerve is correct
Explanation: here is some googlied info as well
The facial nerve (the labyrinthine segment) is the seventh cranial nerve, or simply CN VII. It emerges from the pons of the brainstem, controls the muscles of facial expression, and functions in the conveyance of taste sensations from the anterior two-thirds of the tongue.
Answer:
Explanation:
A woman with type A blood (whose father was type O) meaning her genotype is AO mates with
Man that has type O blood (OO genotype)
Both are heterozygous for MN blood group and both also heterozygous for the FUT1 gene controlling the synthesis of the H substance (Hh)- which determines the expression of the A and B antigen.
Cross
A O M N H h
O AO OO M MM MN H HH Hh
O AO OO N MN NN h Hh hh
Type A- 1/2 O-1/2 type M- 1/4 MN-1/2 N- 1/4, type H- 3/4 h-1/4
Type A with M antigen:
1/2*1/4*3/4 = 3/32
Type A with M and N antigens:
1/2*1/2*3/4 = 3/16
Type A with N antigen:
1/2*1/4*3/4 = 3/32
Type O with M antigen:
1/2*1/4*3/4= 3/32
Type O with M and N antigens:
1/2*1/2*3/4 = 3/16
Type O with N antigen:
1/2*1/4*3/4 = 3/32.
The 3/4 value comes from the expression of Hh-3/4 (this determines if the A and B Angie will be expressed).