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kap26 [50]
3 years ago
5

For two autosomal dominant genes, what is the probability that a cross between two heterozygotes (i.e. AaBb x AaBb) will produce

an offspring with the recessive trait for both genes?
Biology
1 answer:
oksian1 [2.3K]3 years ago
7 0

Answer:

1 in 16

Explanation:

When two heterozygotes (AaBb x AaBb) for two autosomal genes are crossed the expected probability for the offspring is 9 A-B-, 3 A-bb, 3 aaB- and 1 aabb. In other words, out of sixteen offspring, 9 are expected to be dominant on both genes (either homozygous AA or BB or heterozygous Aa or Bb), 3 are expected to be dominant on the A gene but recessive on the b gene, 3 are expected to be recessive on the a gene but dominant on the A gene, and only 1 is expected to be recessive on both genes aabb.

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More solar energy reaches the equatorial regions than the polar regions because the equatorial regions
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However the other regions may receive direct sun rays but for far more limited periods.  In the months of July and August (summer months), the northern hemisphere is tilted towards the sun and receives the most  direct  rays. The opposite occurs in December and January when it is tilted away from the sun and thus winter sets in, whereas the southern hemisphere is at this time tilted toward the sun and receives the most direct sun rays.


4 0
3 years ago
Mexican hairless dogs are hairless because of a dominant allele of a particular gene. Homozygous dominant dogs die in utero (bef
crimeas [40]

Answer:

50%

Explanation:

Both parent's genotype is Bb because they are hairless and alive.

If it has a homozygous dominant genotype (BB), the dog will die in utero.

If it has a heterozygous genotype (Bb), the dog will be hairless but won't die.

If it has a homozygous dominant genotype (bb), the dog will have hair.

The ratio of BB:Bb:bb is 1:2:1 meaning that there is a 50% probability of having a live hairless puppy.

Hope this helps! <3

8 0
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