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BartSMP [9]
3 years ago
11

The null and alternative hypotheses are given. Determine whether the hypothesis test is​ left-tailed, right-tailed, or​ two-tail

ed. What parameter is being​ tested? Upper H 0H0​: muμ equals= 66 Upper H 1H1​: muμ less than< 6
Mathematics
1 answer:
aleksandrvk [35]3 years ago
5 0

Answer: The hypothesis test is left-tailed test.

The parameter tested here is population mean.

Step-by-step explanation:

Given : The null and alternative hypotheses are as follows:

H_0:\mu=6

H_1:\mu

We can see that the parameter tested here is population mean.

Also, the type of test depends on the alternative hypothesis.

Since the alternative hypothesis is left-tailed so the hypothesis test is left-tailed test.

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.<br><br> y = x2 + 3<br> y = x + 5
ddd [48]
I assume you mean x squared in the first equation

Because both are equal to y, they are equal to each other so x + 5 = x^2 +3
If we then move everything over to one side, we get x^2 - x - 2 = 0

Then factorise it to (x-2)(x+1) = 0
And solve both parts separately

x + 1 = 0
x = -1

x-2 = 0
x = 2

Sub both values into the simplest equation in this case y=x+5
to get y = 4 and y = 7
7 0
1 year ago
Does the graph represent a function?
fomenos

Hey there!

No, the graph is not a function because it has two of the same inputs, (7, -6) and (7, -7).

It also can't be a linear function because the graphs are not pointed to form a straight line.

Hope this helps!

Have a great day!

8 0
3 years ago
Read 2 more answers
Please someone help, give the right answer it’s important
dangina [55]

9514 1404 393

Answer:

  (4)

Step-by-step explanation:

The fact that GH is the perpendicular bisector of EF means EM = FM and all of the angles at M are congruent.

It does not say anything about the relative sizes of HM and GM, so we cannot conclude HM and GM are congruent.

5 0
3 years ago
Please i’ll make u brainliest
Nikitich [7]
I think 35/70 is the answer
6 0
3 years ago
Find the two geometric means between -32 and 4.show your solution​
Elina [12.6K]
-32, __, __, 4
a4 = a1r^4-1
4 = -32r^3
-4/32 = r^3
-1/8 = r^3
r = -1/2 common ratio

a2 = a1r = -32(-1/2) = 16
a3 = a2r = 16(-1/2) = -8




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Hope this helps you
3 0
3 years ago
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