Since there are no special paameters mentioned to solve the problem, algebra will be employed.
What we have so far:
Total debit = $<span>12,200
Total credit = $</span><span>11,500
Total transactions = </span>Total credit - Total debit<span>
Final balance = $</span><span>5,000
To solve:
Let us use the working equation: Initial Balance = Final Balance + |Total Transactions|
Initial Balance = </span>$5,000 + |$11,500 - $12,200|
Initial Balance = $5,000 + |-$700| <--- remember that -$700 is an absolute value which makes it positive.
Initial Balance = $5,700 <--- What we are looking for.
Checking:
Early May: $5,700
Around May : $5,700 - Total Debit (Assumption)
Around May : $5,700 - $12,200 = -$6,500 (Assumption)
Around May: -$6,500 + Total Credit (Assumption)
Around May: -$6,500 + $11,500 = $5,000 (Assumption)
31st of May: $5,000 <--- Proven
∴The answer is: $5,700, the initial balance at the beginning of May.
for how many days though..
<h3>Given</h3>
2 milks + 5 waters + 8 chips = $25
water cost = 2×chips cost
milk cost = $1.50 + water cost
<h3>Find</h3>
The cost of each: milk, water, chips.
<h3>Solution</h3>
Let m, w, and c represent the costs of milk, water, and chips, respectively. We can write the given relations more compactly as
... 2m + 5w + 8c = 25
... w = 2c
... m = w + 1.5
We can substitute for w everywhere using the second equation. This gives us
... m = 2c +1.5
... 2(2c+1.5) + 5(2c) + 8(c) = 25
... 22c + 3 = 25
... 22c = 22
... c = 1
Then
... m = 2·1 + 1.5 = 3.5
... w = 2·1 = 2
A gallon of milk costs $3.50, a bottle of water costs $2.00, a bag of chips costs $1.00.
Answer:
1/380
Step-by-step explanation:
<u>Probability of Bob's name drawn first is:</u>
- 1/20 as there are 20 people with equal chance
<u>And probability of Laquisha's name drawn second is: </u>
- 1/19 as there are 19 people left with equal chance
<u>Probability of the two events happening is: </u>
- 1/20*1/19 = 1/380 product of individual probabilities
