9514 1404 393
Answer:
C. symmetric with respect to the origin
Step-by-step explanation:
A graph must pass the vertical line test to be called the graph of a function. No function will ever be symmetrical with respect to the x-axis, because that would mean it fails the vertical line test.
An even function is symmetrical about the y-axis. An even function has the characteristic that ...
f(-x) = f(x) . . . . an even function
An odd function is symmetrical about the origin. An odd function has the characteristic that ...
f(-x) = -f(x)
__
The given function is f(x) = -1/x. Then the value of f(-x) is ...
f(-x) = -1/-x = 1/x = -f(x)
The given function is an odd function, so is symmetrical about the origin.
Answer:
V2=-20.0155m/s
Step-by-step explanation:
To answer this question we will use the principle of conservation of momentum which is
MtVt=M1V1+M2V2
1) let's find the initial velocity.
We will use,
v=a*t
v=10m/s2*2s = 20 m/s
d=vot+1/2*a*t2
d=0+1/2*10*4
d=20m
2) For the speed of the lighter piece we use,
v22=v12+2ad
0=v12+2*-9.81*(530-20)
v12=10006.2
v1=100.031m/s
3) Computing this in our conservation of momentum equation it will be-
MtVt=M1V1+M2V2
1500kg*20m/s=(1500*1/3)kg*100.031m/s + (1500*2/3)+V2
30000=50015.5+1000V2
Therefore V2=-20.0155m/s.
I think it’s number 2 sorry if it’s wrong!!
K=2.35. You are correct.
Have a nice day! :)
Value of 3 is in the solution set