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4 years ago

Please help me on this

Mathematics

1 answer:

nadya68 [22]4 years ago

3 0

Savings account, retirement savings, value of second car, balance in checking account i believe those are the only ones not positive though

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Identify the terms, coefficients, and constants in the expression 15x+3

VLD [36.1K]

Answer:

coefficients are : 15. constants are: 3

Step-by-step explanation: hope it helps

5 0

3 years ago

HELP ME PLZZ I NEED HELP WITH THIS !!

Mice21 [21]

Answer:

The answer is C.

Step-by-step explanation:

When you look at the number line for C, you can see that it starts from positive 2 and shows the distance all the way to -5.

8 0

3 years ago

How do you reduce 2 1/32

wlad13 [49]

Answer:

I don't think you can reduce this number.

Step-by-step explanation:

There is no common factor between the numbers. Thus it stays the same. Hope this helps .

6 0

3 years ago

Final exam scores are normally distributed with a mean of 74 and a standard deviation of 6. Approximately, what percentage of fi

notka56 [123]

Answer:

81.86%

Step-by-step explanation:

We have been given that final exam scores are normally distributed with a mean of 74 and a standard deviation of 6.

First of all we will find z-score using z-score formula.

$z=\frac{x-\mu}{\sigma}$

$z=\frac{68-74}{6}$

$z=\frac{-6}{6}=-1$

Now let us find z-score for 86.

$z=\frac{86-74}{6}$

$z=\frac{12}{6}=2$

Now we will find P(-1<Z) which is probability that a random score would be greater than 68. We will find P(2>Z) which is probability that a random score would be less than 86.

Using normal distribution table we will get,

$P(-1$

$P(2>Z)=.97725$

We will use formula $P(a$ to find the probability to find that a normal variable lies between two values.

Upon substituting our given values in above formula we will get,

$P(-1$

Upon converting 0.81859 to percentage we will get

$0.81859*100=81.859\approx 81.86$

Therefore, 81.86% of final exam score will be between 68 and 86.

3 0

3 years ago

Help me please please please please

OLga [1]

swipe the picture to the left ←

<h2>#CarryOnLearning</h2>

$\mathfrak{WatanabeHaruto}$

3 0

3 years ago

Please help me on this​

Please help me on this