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Helen [10]
3 years ago
13

Which of the following represents the outcomes for those not in event E and not in event F

Mathematics
1 answer:
maks197457 [2]3 years ago
7 0

Answer:

B

Step-by-step explanation:

the sentences of b option can be

not event É and not event F

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If a constant of proportionality is 1/5, what would the new constant of proportionality be if the x and y axes were flipped? (an
mixas84 [53]

Answer:

5/1 or 5

Step-by-step explanation:

don't take my word for it but if i understand correctly all you have to do is flip the 1 and 5 which is called the recipicoal  

8 0
3 years ago
[-16 (-0.2)]-[(-4)×0.66]
Sergio [31]

[-16(-0.2)] - [(-4)*0.66]

3.2 - (-2.64)

3.2+2.64 = 5.84

So, your answer is 5.84

4 0
4 years ago
suppose f(x) = x2, how does the range of g(x) = f(x) + k compare to the range of f(x)? Where k is any constant value.
anyanavicka [17]
First:  Please use the symbol " ^ " to indicate exponentiation.  Your f(x) should be x^2, not x2.  "x^2" reads "the square of x."

Let y equal g(x) = f(x) + k:  y = <span>g(x) = f(x) + k.  See that "k" is a y value?
If k=1, we merely translate the graph of f(x)=x^2 UP one scale division to obtain the graph of g(x) = f(x) + 1.

So, how does the range of g(x) compare to the range of f(x)? </span>
4 0
3 years ago
Hannah had 30 dollars to spend on 3 gifts. She spent 8 7 10 dollars on gift A and 4 2 5 dollars on gift B. How much money did sh
Dimas [21]

Answer: \$16\dfrac{9}{10}

Step-by-step explanation:

Given

Hannah had 30 dollars

Money spent on gift A

8\ \dfrac{7}{10}=\dfrac{8\times 10+7}{10}=\dfrac{87}{10}

money spent on gift B

4\ \dfrac{2}{5}=\dfrac{22}{5}

Money spent on gift C

\Rightarrow \text{Total-Money spent on (A+B)}\\\\\Rightarrow 30-\dfrac{87}{10}-\dfrac{22}{5}=30-\dfrac{87}{10}-\dfrac{44}{10}\\\\\Rightarrow \dfrac{300-87-44}{10}=\dfrac{169}{10}\\\\\Rightarrow \$16\ \dfrac{9}{10}

5 0
3 years ago
Two students use different methods to solve this multiplication problem: 1/2 • -4 4/5
sesenic [268]

Solution:

\frac{1}{2}\times-4 \frac{4}{5}

As one of the fraction is a proper fraction and another one is Mixed fraction.

There are two methods of solving it.

1. \frac{1}{2}\times-4 \frac{4}{5}=\frac{1}{2} \times \frac{-24}{5}=\frac{-12}{5}=-2\frac{2}{5}

2. \frac{1}{2}\times-4 \frac{4}{5}=\frac{1}{2}[-4-\frac{4}{5}]=\frac{1}{2}\times (-4)+\frac{1}{2}\times\frac{-4}{5}=-2+\frac{-2}{5}=\frac{-10-2}{5}=\frac{-12}{5}=-2\frac{2}{5}→→Here i have used Distributive property with respect to addition and Subtraction i.e a×(b+c)= a ×b + a×c or a×(b-c)=a×b-a×c

Now, you can fill the blanks by yourself.

5 0
4 years ago
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