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Leni [432]
3 years ago
9

During Sunday's game against the Nuggets, Lebron James scored 26 points. If the laker scored 105 points to win, what percentage

of total was Lebrons'?​
Mathematics
2 answers:
Advocard [28]3 years ago
8 0

Answer:

I think the lakers are winning the finals but 25 percent

Step-by-step explanation:

ladessa [460]3 years ago
6 0

Answer:

About 25%

Step-by-step explanation:

26/105=.247619 and a whole bunch of other numbers. Simplified to the nearest 100th, it's .25. Switch it to percent, the answer is about 25%

You might be interested in
Let’s assume that human body temperatures are normally distributed with a mean of 98.20° F and a standard deviation of 0.62° F.
uysha [10]

Answer: It is such a small percentage of the population that would be considered to have fever at that level.

So, it is not appropriate stringent standard.

Step-by-step explanation:

Since we have given that

Mean = 98.20°F

Standard deviation = 0.62°F

If  Bellevue Hospital in New York City uses 100.6°F as the lowest temperature considered to be a fever.

So, \bar{X}=100.6^\circ F

So, using the normal distribution, we first find the value of z.

z=\dfrac{\bar{x}-\mu}{\sigma}\\\\x=\dfrac{100.6-98.2}{0.62}\\\\z=3.87

Since z = 3.87

So, p = 0.0001 =0.1%

So,It is such a small percentage of the population that would be considered to have fever at that level.

So, it is not appropriate stringent standard.

4 0
3 years ago
2. A cone has a volume 7,065 in.3 and a<br>height of 30 inches. What is the radius of the<br>cone?​
kap26 [50]

Answer:

r=8.66025403784

Step-by-step explanation:

7065=π(r squared)X30

7065=94.2(r squared)

7065÷94.2=r squared

√75=r squared

8.66025403784=r

5 0
3 years ago
Determine the x- and y- intercepts for the graph defined by the given equation.<br> y = 7x + 3
pantera1 [17]

Answer:

 intercept is 3 

X intercept is -3/7

5 0
3 years ago
Read 2 more answers
What is the value of x
kati45 [8]

Answer:8

Step-by-step explanation:

6 0
2 years ago
Inverse laplace of [(1/s^2)-(48/s^5)]
Katen [24]
**Refresh page if you see [ tex ]**

I am not familiar with Laplace transforms, so my explanation probably won't help, but given that for two Laplace transform F(s) and G(s), then \mathcal{L}^{-1}\{aF(s)+bG(s)\} = a\mathcal{L}^{-1}\{F(s)\}+b\mathcal{L}^{-1}\{G(s)\}

Given that \dfrac{1}{s^2} = \dfrac{1!}{s^2} and -\dfrac{48}{s^5} = -2\cdot\dfrac{4!}{s^5}

So you have \mathcal{L}^{-1}\left\{\dfrac{1}{s^2} - 2\cdot\dfrac{4!}{s^5}\right\} = \mathcal{L}^{-1}\left\{\dfrac{1}{s^2}\right\} - 2\mathcal{L}^{-1}\left\{\dfrac{4!}{s^5}\right\}

From Table of Laplace Transform, you have \mathcal{L}\{t^n\} = \dfrac{n!}{s^{n+1}} and hence \mathcal{L}^{-1}\left\{\dfrac{n!}{s^{n+1}}\right\} = t^n

So you have \mathcal{L}^{-1}\left\{\dfrac{1}{s^2}\right\} - 2\mathcal{L}^{-1}\left\{\dfrac{4!}{s^5}\right\} = \boxed{t-2t^4}.

Hope this helps...
7 0
3 years ago
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