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Veronika [31]
3 years ago
8

*20 points*

Mathematics
2 answers:
ioda3 years ago
5 0
So hmm notice the picture below

simply get the area of the segment, and subtract it from the area of the circle, what's left, is the difference

notice your circle, has a radius "r" of 18

mario62 [17]3 years ago
3 0

Answer:

Hence, Total area of shaded region=  (243π+162)  ft²

Step-by-step explanation:

Area of shaded region can be calculated as

  Area of right triangle + area of the circle below the right triangle

Area of circle=πr²  (360° is covered)

360°-90°=270°

i.e.    (270÷360)°= 3/4 part of the circle is covered

So, area of circle below the right triangle=  3×π×18×18/4

                                                                   =  243π

area of right triangle=  base×height/2

                                =   18×18/2

                               =   162  

Hence, total area of shaded region=  (243π+162)  ft²

Hence, option A is correct.  

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Look at the figure. Name the postulate or theorem you can use to prove the triangles congruent.
valentinak56 [21]

Answer:

AAS Theorem

Step-by-step explanation:

we can see that

angle ZVY ≅ angle WVY

angle VZY ≅ angle VWY

side VY shared by both triangles.

by Angle- Angle- SIde (AAS), the triangles are congruent.

4 0
3 years ago
What is two mixed numbers that have the sum of 3
Juli2301 [7.4K]
Mixed numbers are a mix of a whole number and a fraction
a easy one is
1 and 1/4+1 and 3/4
1 and 1/2 +1 and 1/2
1 and 9/10 and 1 and 1/10
etc
6 0
3 years ago
Which of the following is the product of the rational expressions shown below? 7x/x-4•x/x+7
Gre4nikov [31]
<h2>The product of the rational expressions\dfrac{7x}{x-4}.\dfrac{x}{x+7} = \dfrac{7x^2}{x^2+3x-28}.</h2>

Step-by-step explanation:

We have,

\dfrac{7x}{x-4}.\dfrac{x}{x+7}

To find, the product of the rational expressions \dfrac{7x}{x-4}.\dfrac{x}{x+7} = ?

∴ \dfrac{7x}{x-4}.\dfrac{x}{x+7}

= \dfrac{7x.x}{(x-4)(x+7)}

= \dfrac{7x^2}{(x(x+7)-4(x+7)}

= \dfrac{7x^2}{x^2+7x-4x-28}

= \dfrac{7x^2}{x^2+3x-28}

Thus, the product of the rational expressions \dfrac{7x}{x-4}.\dfrac{x}{x+7} = \dfrac{7x^2}{x^2+3x-28}.

7 0
3 years ago
I need helpppp plssss anyone I’m not the best at math :/
Ulleksa [173]

Answer:

C

Step-by-step explanation:

7 0
3 years ago
Solve sin 0 + 1 = cos20 on the interval 0 ≤ 0 &lt; 2pi. Show work please!
yan [13]

Answer:

\theta=\frac{\pi}{2},\frac{3\pi}{2}\frac{2\pi}{3}\frac{4\pi}{3}

Step-by-step explanation:

You need 2 things in order to solve this equation:  a trig identity sheet and a unit circle.

You will find when you look on your trig identity sheet that

cos(2\theta)=1-2sin^2(\theta)

so we will make that replacement, getting everything in terms of sin:

sin(\theta)+1=1-2sin^2(\theta)

Now we will get everything on one side of the equals sign, set it equal to 0, and solve it:

2sin^2(\theta)+sin(\theta)=0

We can factor out the sin(theta), since it's common in both terms:

sin(\theta)(2sin(\theta)+1)=0

Because of the Zero Product Property, either

sin(\theta)=0 or

2sin(\theta)+1=0

Look at the unit circle and find which values of theta have a sin ratio of 0 in the interval from 0 to 2pi.  They are:

\theta=\frac{\pi}{2},\frac{3\pi}{2}

The next equation needs to first be solved for sin(theta):

2sin(\theta)+1=0 so

2sin(\theta)=-1 and

sin(\theta)=-\frac{1}{2}

Go back to your unit circle and find the values of theta where the sin is -1/2 in the interval.  They are:

\theta=\frac{2\pi}{3},\frac{4\pi}{3}

7 0
3 years ago
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