Question

Factoring the Difference of Two perfect squares factor: 49p^2-64y^2 1-25x^2

Answer 1

Using formula of difference of two squares a^2 -b^2 =(a-b)(a+b) we get 

49p^2 -64y^2 = (7p -8y)(7p +8y)

and 

1 - 25x^2 = (1 -5x)(1 +5x)

hope helped