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Harrizon [31]
2 years ago
10

Directions-Write an exponential function to model each situation. Then find the value of the function after the given amount of

time.
Questions-The value of a textbook is $69 and decreases at a rate of 15% per year for 11 years. and y=?
Mathematics
1 answer:
nignag [31]2 years ago
8 0

Answer:

We can now write this is a function of time in years leading to

f

(

x

)

=

200

(

.94

)

x

f

(

5

)

≈

147

Explanation:

Firs you should consider that if its exponential then it has some form similar to

3

x

. Where we have some known part (3) and the unknown part (

x

) that we are trying to find out. Mathematically we can say it has the form

a

x

. In this case we know what the

a

is and that is the entire population that was given to us. We know over time it will change but why are we even using the exponential model.

Well it turns out that if you multiply some value over and over again it has this form. Example we multiply

2

⋅

2

⋅

2

⋅

2

=

2

4

. So if something doubled over time then this is what would happen.

Now the problem is that it will continue to decrease at the same rate leading to

a

⋅

(

.94

)

because only

94

%

of the population remains each year. After two years

a

⋅

(

.94

)

⋅

(

.94

)

. We can now write this is a function of time in years leading to

f

(

x

)

=

200

⋅

(

.94

)

x

f

(

5

)

≈

147

Step-by-step explanation:

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Section 5.2 Problem 17:
Elina [12.6K]

This DE has characteristic equation

4r^2 - 12r + 9r = (2r - 3)^2 = 0

with a repeated root at r = 3/2. Then the characteristic solution is

y_c = C_1 e^{\frac32 x} + C_2 x e^{\frac32 x}

which has derivative

{y_c}' = \dfrac{3C_1}2 e^{\frac32 x} + \dfrac{3C_2}2 x e^{\frac32x} + C_2 e^{\frac32 x}

Use the given initial conditions to solve for the constants:

y(0) = 3 \implies 3 = C_1

y'(0) = \dfrac52 \implies \dfrac52 = \dfrac{3C_1}2 + C_2 \implies C_2 = -2

and so the particular solution to the IVP is

\boxed{y(x) = 3 e^{\frac32 x} - 2 x e^{\frac32 x}}

8 0
2 years ago
B(x)=|x+4| what is b(-20)​
sattari [20]

Answer:

16

Step-by-step explanation:

plug in -20 for x to get |-20+4|

that is |-16| but the absolute value of it is 16

4 0
3 years ago
2:x and 12:18 a-3, b-4, c-6
nirvana33 [79]

The Corrected Problem is :

2:x and 12:18 identify the value of x that makes each pair of ratios equivalent .

Solution:

If a pair of Ratios are equivalent then we can write

\frac{2}{x}=\frac{12}{18}\\ \\ \text{Simplify we get}\\ \\ 12x=36\\ \\ \text{Divide both the sides by 12 we get}\ \\ \\ \frac{12x}{12}=\frac{36}{12}\\ \\  x=3\\ \\ \text{Hence the required value of x is 3}\\

3 0
3 years ago
Read 2 more answers
Simplify 9 log9 (7) is the answer 7
Aleks04 [339]
log_ab=c\ \ \ \Leftrightarrow\ \ \ a^c=b\\\\log_97=x\ \ \ \Leftrightarrow\ \ \ 9^x=7\\\\9^x=7\ \ \ (and \ \ \ x=log_97)\ \ \ \Rightarrow\ \ \ 9^{\big{log_97}}=7
3 0
3 years ago
PLEASE HELP! DUE TODAY :))
Aleonysh [2.5K]

Step-by-step explanation:

do like the picture I sent

3 0
3 years ago
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