he mass defect of the helium nucleus ⁴He₂ is 0.030377 u
Further explanation
Mass defect means the difference between the mass of particles forming an atom with an atomic mass.
Δm = mass defect ( u )
mp = mass of proton ( u )
me = mass of electron ( u )
mn = mass of neutron ( u )
M = atomic mass ( u )
A = mass number
Z = atomic number
Let us now tackle the problem !
Given :
Unknown :
Δm = ?
Solution :
Learn more
Rutherford’s major achievements : brainly.com/question/1552732
Unit of radius of an atom : brainly.com/question/1968819
Fusion : brainly.com/question/11395223
Answer details
Grade: College
Subject: Physics
Chapter: Nuclear Physics
Keywords: Mass , Defect , Nucleon , Number , Atomic , Proton , Electron , Neutron
Question:
A) 12
B) 29
C) 2.1 × 10⁻²
D) 8.7 × 10⁻²
E) 47
Answer:
The correct option is;
E) 47
Explanation:
Kc, which is the equilibrium constant of a chemical reaction is derived by finding the ratio between the product of the equilibrium concentration of the product raised to their respective coefficients to the product of the equilibrium concentration of the reactants also raised to their respective coefficients.
Here we have;
[H₂] = 0.14 M
[Cl₂] = 0.39 M
[HCl] = 1.6
The reaction is given as follows;
H₂ (g) + Cl₂ (g) ⇄ 2HCl (g)
The formula for Kc is given as follows;
![Kc = \frac{[HCl]^2}{[H_2][Cl_2]} = \frac{1.6^2}{0.14 \times 0.39} = 46.886](https://tex.z-dn.net/?f=Kc%20%3D%20%5Cfrac%7B%5BHCl%5D%5E2%7D%7B%5BH_2%5D%5BCl_2%5D%7D%20%3D%20%5Cfrac%7B1.6%5E2%7D%7B0.14%20%5Ctimes%200.39%7D%20%20%3D%2046.886)
Therefore, the Kc for the reaction is approximately equal to 47.
the control rods absorb extra neutrons keeping them from causing to many uranium atoms to split to quickly.
Answer:
it has to be a no cap !! buh
1) molar mass of the C6H8O<span>6, you need to consult the atomic weight of the C, H and O atoms that are in the periodic table: C is 12; H is 1; O is 16
(12x6)+(1x8)+(16x6)= 176g/mol
</span><span>176 g = 1 mol
0,5 g = x mol 500mg= 0,5 grams
molar mass = mass÷ moles
176 = 0,5÷ x
x= 2,84 x 10⁻³ mol
2) To find the number of molecules present in those </span>2,84 x 10⁻³ mol we need to multiple the moles by the <span>Avogadro's constant
No. of molecules = Avogadro's constant x n° of moles
</span>No. of molecules = 6.022 x 10²³ x 2,84 x 10⁻³ <span>
= 1.71 x 10²¹ molecules of vit C. </span>
