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adoni [48]
3 years ago
10

What Size container do you need to hold 0.0459 mol of N2 gas at stp

Chemistry
1 answer:
Allushta [10]3 years ago
4 0
Hello!

You need to calculate the volume of the container. To calculate the volume of this amount of N₂ gas we need to make the assumption that N₂ behaves like an ideal gas. 

1 mole of an ideal gas under Standard Temperature and Pressure occupies 22,4 L so the calculations are as follows:

0,0459 mol N_2* \frac{22,4 L}{1 mol N_2}= 1,028 L

So, the volume of the container should be 1,028 L or more.

Have a nice day!
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Answer:

b) a rubber tire

Explanation:

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2 years ago
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Which would be the best to neutralize a large acid spill in your school lab: sodium hydroxide or baking soda? Explain.
nadya68 [22]

Consider the acid spill. It is already starting to do nasty things to, say, the floor or counter. So you grab the bottle of 10% NaOH and pour some on the spill. All of a sudden, you get a great deal of heat, and you don't have any visual evidence whether your put on too little or too much. But you have added more liquid to the spill, generated more heat, and will get more damage. You have made a bigger mess, and if you added too much, you then have a neutralization problem to deal with.  

And if it is something like a strong sulfuric acid solution, adding sodium hydroxide solution will be extremely exothermic, and you could get some really nasty results.  

So now approach the spill with a handful of baking soda. You sprinkle it on the spill. It fizzes, and carbon dioxide is given off. That actually, in a very tiny way, moderates the temperature of the neutralization. And you can keep adding baking soda until the fizzing stops, and then perhaps some water to mix everything well. But what you have done is kept the volume to a minimum, added a neutralization agent that has a visible endpoint (no more gas being given off), and you don't suddenly have a huge amount of highly basic solution because you added too much.  

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5 0
3 years ago
Exactly 5000 mL of air at 223K is warmed and has a new volume of 8.36 liters. What is the new temperature?
34kurt

Answer:

The new temperature is 373 K

Explanation:

Step 1: Data given

Volume air = 5000 mL = 5.0 L

Temperature = 223K

New volume = 8.36 L

Step 2: Calculate the new temperature

V1/T1 = V2/T2

⇒V1 = the initial volume = 5.0 L

⇒T1 = the initial temperature = 223 K

⇒V2 = the new volume = 8.36 L

⇒T2 = the new temperature

5.0/223 = 8.36 /T2

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7 0
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Leni [432]

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Critical value: z_{\alpha/2}=1.96

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Standard deviation : \sigma=2.2

The formula to find the confidence interval is given by :-

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i.e. 28.6\pm (1.96)\dfrac{2.2}{\sqrt{30}}

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Which step will decrease the pressure of a gas inside a closed cubical container? increasing the number of moles of gas decreasi
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At constant volume, pressure of the gas will decrease on decreasing the temperature or vice versa.

Decreasing the temperature inside the container will decrease the pressure of a gas inside a closed cubical container.

8 0
3 years ago
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