Answer: 15.850
Explanation:
The conversion used from liters to gallons is:
1 L = 0.264172 gallon
The conversion used from sec to min is:
60 sec = 1 min
1 sec =
We are asked: liters/sec = gallons/min
Therefore, to convert from liters/second to gallons/minute, multiply the number of liters/second by 15.850.
Mobile phase is the liquid or organic solvent present in the developing tank or beaker by Ayesha zulfiqar
(Hoped that helped)
Answer:104.6cm^3
Explanation:
V of a cylinder =πr2h
V = pi((1.045cm)^2)(30.48)
V = 104.57cm^3
Explanation:
<h3>
Answer:</h3>
Gas law : Boyle's law
New pressure: 66.24 atm
<h3>
Explanation:</h3>
Concept tested: Gas laws (Boyle's law)
<u>We are given,</u>
- Initial pressure, P₁ = 2.86 atm
- Initial volume, V₁ = 8472 mL
- New volume, V₂ IS 365.8 mL
We need to determine the new pressure, P₂
- According to Boyle's law , the volume of a fixed mass of a gas and the pressure are inversely proportional at constant temperature.
- That is,
![P\alpha \frac{1}{V}](https://tex.z-dn.net/?f=P%5Calpha%20%5Cfrac%7B1%7D%7BV%7D)
- This means , PV = k (constant)
- Therefore; P₁V₁ = P₂V₂
- Rearranging the formula, we can get the new pressure, P₂
P₂ = P₁V₁ ÷ V₂
= (2.86 atm × 8472 mL) ÷ 365.8 mL
= 66.24 atm
Therefore, the new pressure is 66.24 atm
Answer:
5 × 10^-4 L
Explanation:
The equation of the reaction is;
2KClO3 = 2KCl + 3O2
Number of moles of KClO3 = 13.5g/122.5 g / mol = 0.11 moles
From the stoichiometry of the reaction;
2 moles of KClO3 yields 3 moles of O2
0.11 moles of KClO3 yields 0.11 × 3/2 = 0.165 moles of oxygen gas
From the ideal gas equation;
PV= nRT
P= 85.4 × 10^4 KPa
V=?
n= 0.165
R= 8.314 J K-1 mol-1
T= 40+273 = 313K
V= 0.165 ×8.134 × 313/85.4 × 10^4
V=429.4/85.4 × 10^4
V= 5 × 10^-4 L