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maw [93]
3 years ago
11

You and a friend are rolling two 6-sided number cubes and placing bets on the sum of the outcome. is it better to place a bet on

a sum of 3, 4, 7, or 11?
Mathematics
2 answers:
mote1985 [20]3 years ago
6 0

Answer:

It is better to bet on 7.

Step-by-step explanation:

It is given that,

We are rolling two 6-sided numbered cubes and placing bets on the 'sum of the outcome'.

So, the pair of numbers will be the possible options for the outcome to be their sum.

Now, the possibility to have the sum of 3, 4, 7 and 11 are:

3 = 1+2 i.e. only one pair is the possibility

4 = 1+3 = 2+2 i.e there are two pairs as the possibility

7 =  1+6 = 2+5 = 3+4 i.e. there are three possible pairs

11 = 5+6 i.e. only one pair is the possibility

So, the maximum possibility of a sum to be the outcome is when the sum = 7 i.e. there are 3 possible pairs for the sum to be 7.

Hence, 7 has the highest possibility to become the outcome.

So, It is better to bet on 7.

Zina [86]3 years ago
4 0
To solve for this, we need to figure out the sum of any two numbers on the dice that will become a pair factor for the listed answers.
What I mean by that is that we need to find the probability between how many two numbers will sum up to the answer.

3 can be 1 + 2, that's it. 3 has a probability of (1).
4 has a sum of 1 + 3, and 2 + 2, that's it. 4 has a probability of (2).
7 has a sum of 1 + 6, 2 + 5, and 3 + 4. 7 has a probability of (3).
11 has a sum of 5 + 6, that's it. 11 has a probability of (1).

The numbers in parenthesis are the probabilities.
7 has the highest number, so 7 has the highest probability.

Your answer is: 7.

I hope this helps!
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3 years ago
What type of graph consist of a number of points that may or may not be associated with each other? A) Line Graph B) Circle Grap
tatyana61 [14]
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7 0
3 years ago
give an example of a convergent infinite series whose sum equal 3/5. explain how you know your series converges and write out wo
krek1111 [17]

Answer:

The series 1/5, 2/15, 4/45, 8/135... converges and sums up to 3/5

Step-by-step explanation:

Consider the infinite geometric series

1/5, 2/15, 4/45, 8/135...

With first term, a=1/5

common ratio, r = ⅔

The series converge because the common ratio, |r|<1.

The sum to infinity of a geometric series, S= a/(1-r)

S= 1/5 ÷ (1-⅔) = 1/5 ÷ 1/3 = 3/5

Therefore, the geometric series 1/5, 2/15, 4/45, 8/135... sums up to 3/5.

5 0
3 years ago
What can I do with a coordinations and the slope
Mnenie [13.5K]

You can plot a linear equation, if you are given the coordinates and the slope for THE SAME line.

Assuming you have those, the first step is to find the y-intercept.

That is done by replacing x and y in the general formula by their coordinated counterparts, and replacing m by the slope that is given to you.

Let's assume the coordinates you are given are (5,10), and the slope you are given is 1.

By substituting into the general formula...

y=mx+c\\(10)=(1)(5)+c\\10=5+c\\10-5=c\\c=5

...we can see that it is possible to find the y-intercept (c).

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7 0
3 years ago
Please help and show how you got the answer:
kari74 [83]

4 - 6n = 60 - 2n   <em>subtract 4 from both sides</em>

-6n = 56 - 2n    <em>add 2n to both sides</em>

-4n = 56    <em>divide both sides by (-4)</em>

n = - 14


-7 + 11p = 3p - 47       <em>add 7 to both sides</em>

11p = 3p - 40      <em>subtract 3p from both sides</em>

8p = -40      <em>divide both sides by 8</em>

p = - 5


3a - 28 - 7a = 10a          <em>combine like terms</em>

(3a - 7a) - 28 = 10a

-4a - 28 = 10a       <em>add 28 to both sides</em>

-4a = 10a + 28       <em>subtract 10 from both sides</em>

-14a = 28     <em>divide both sides by (-14)</em>

a = - 2


17 - 5r + 9r = 12 + 6r - 1       <em>combine like terms</em>

17 + (-5r + 9r) = (12 - 1) + 6r

17 + 4r = 11 + 6r      <em>subtract 17 from both sides</em>

4r = -6 + 6r     <em>subtract 6r from both sides</em>

-2r = -6      <em>divide both sides by (-2)</em>

r = 3


8(y - 7) = -2(y + 3)    <em>use distributive property: a(b + c) = ab + ac</em>

(8)(y) + (8)(-7) = (-2)(y) + (-2)(3)

8y - 56 = -2y - 6       <em>add 56 to both sides</em>

8y = -2y + 50     <em>add 2y to both sides</em>

10y = 50    <em>divide both sides by 10</em>

y = 5


-3(8k + 5) = 3(9 - k)      <em>use distributive property: a(b + c) = ab + ac</em>

(-3)(8k) + (-3)(5) = (3)(9) + (3)(-k)

-24k - 15 = 27 - 3k      <em>add 15 to both sides</em>

-24k = 42 - 3k      <em>add 3k to both sides</em>

-21k = 42     <em>divide both sides by (-21)</em>

k = -2


2(3v - 5) = 2(v - 11) - 4   <em>use distributive property: a(b + c) = ab + ac</em>

(2)(3v) + (2)(-5) = (2)(v) + (2)(-11) - 4

6v - 10 = 2v - 22 - 4

6v - 10 = 2v - 26      <em>add 10 to both sides</em>

6v = 2v - 16      <em>subtract 2v from both sides</em>

4v = -16      <em>divide both sides by 4</em>

v = -4


-2/3 (15x + 3) -3x - 9    <em>use distributive property: a(b + c) = ab + ac</em>

= (-2/3)(15x) + (-2/3)(3) - 3x - 9

= (-2)(5x) - 2 - 3x - 9

= -10x - 2 - 3x - 9                 <em>combine like terms</em>

= (-10x - 3x) + (-2 - 9)

= -13x - 11


3(1 - 9a) + 22a = 2(2a - 9) - 15

<em>use distributive property: a(b + c) = ab + ac</em>

(3)(1) + (3)(-9a) + 22a = (2)(2a) + (2)(-9) - 15

3 - 27a + 22a = 4a - 18 - 15          <em>combine like terms</em>

3 + (-27a + 22a) = 4a + (-18 - 15)

3 - 5a = 4a - 33      <em>subtract 3 from both sides</em>

-5a = 4a - 36       <em>subtract 4a from both sides</em>

-9a = -36      <em>divide both sides by (-9)</em>

a = 4


-3(3m - 10) - 7 = -5(m + 1) + 3m

<em>use distributive property: a(b + c) = ab + ac</em>

(-3)(3m) + (-3)(-10) - 7 = (-5)(m) + (-5)(1) + 3m

-9m + 30 - 7 = -5m - 5 + 3m           <em>combine like terms</em>

-9m + (30 - 7) = (-5m + 3m) - 5

-9m + 23 = -2m - 5     <em>subtract 23 from both sides</em>

-9m = -2m - 28        <em>add 2m to both sides</em>

-7m = -28      <em>divide both sides by (-7)</em>

m = 4

6 0
3 years ago
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