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taurus [48]
3 years ago
15

I am so confused please help

Mathematics
2 answers:
Lemur [1.5K]3 years ago
6 0

Answer:

a. 2\sqrt{31}

b. 3

c.  3\sqrt{5}

d. 2\sqrt{3}

Step-by-step explanation:

This is a simple quadratic formula "substitution".

Essentially what you do is replace the "b" in the formula given above, with a "b" value from your given choices, same goes for "a" and "c" values.

You replace them and then solve the quadratic formula equation.

Ex. For the first set of values in your question, you make the formula into:

\sqrt{2^2-4(5)(-6) And there you would solve normally.

2 squared is 4, so you get 4 - [4 * 5 * -6]

Which after solving leaves you with: \sqrt{2^2+124}

Then you do Prime Factorization of 124, leaving you with: \sqrt{2^2*31}

Then you apply the radical rule, leaving you with: 2\sqrt{31}

Marysya12 [62]3 years ago
3 0

Step-by-step explanation:

This is a simple quadratic formula "substitution".

Essentially what you do is replace the "b" in the formula given above, with a "b" value from your given choices, same goes for "a" and "c" values.

You replace them and then solve the quadratic formula equation.

Ex. For the first set of values in your question, you make the formula into:

And there you would solve normally.

2 squared is 4, so you get 4 - [4 * 5 * -6]

Which after solving leaves you with:

Then you do Prime Factorization of 124, leaving you with:

Then you apply the radical rule, leaving you with:

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A random sample of the actual weight of 5-lb bags of mulch produces a mean of 4.963 lb and a standard deviation of 0.067 lb. If
dsp73

Answer: B) 4.963±0.019.

Step-by-step explanation:

Confidence interval for population mean ( when population standard deviation is not given) is given by :-

\overline{x}\pm t^*\dfrac{s}{\sqrt{n}}

, where \overline{x} = Sample  mean

n= Sample size

s= sample standard deviation

t* = critical t-value.

As per given:

n= 50

Degree of freedom = n-1 =49

\overline{x}= 4.963\ lb

s= 0.067 lb

For df = 49 and significance level of 0.05 , the critical two-tailed t-value ( from t-distribution table) is 2.010.

Now , substitute all values in the formula , we get

4.963\pm (2.010)\dfrac{0.067}{\sqrt{50}}\\\\ 4.963\pm (2.010)(0.0094752)\\\\ 4.963\pm0.019045152\approx4.963\pm0.019

Hence,  a 95% confidence interval for the mean weight (in pounds) of the mulch produced by this company is 4.963\pm0.019.

Thus , the correct answer is B) 4.963±0.019.

7 0
3 years ago
5/8+1/4 plz help me
slava [35]
Answer 7/8 or .875 in decimal form
6 0
3 years ago
72 boxes sold out of 90 boxes what percent sold
Vaselesa [24]

Answer:

80%

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
A random sample of 133 people was taken from a very large population. Sixty-five of the people in the sample were females.The st
rjkz [21]

Answer: 0.0433

Step-by-step explanation:

Given: Sample size : n= 133

The number of females in sample = 65

Then the proportion of females : P=\dfrac{65}{133}

The formula to calculate the standard error of the proportion is given by :-

S.E.=\sqrt{\dfrac{P(1-P)}{n}}

\Rightarrow S.E.=\sqrt{\dfrac{\dfrac{65}{133}(1-\dfrac{65}{133})}{133}}\\\\\Rightarrow\ \Rightarrow S.E.=0.0433444676341\approx0.0433

Hence, the standard error of the proportion of females is 0.0433.

6 0
3 years ago
Find two consecutive even integers such that the square of the first, decreased by the second is 130
marta [7]
Let's make the first even integer m and the second even integer n. The square of the first, decreased by the second is 130 is:

m^{2}-n=130  ---> Add n to each side
m^{2}=130+n ---> Take the square root of each side
m=±\sqrt{130+n}

Let's look at the first square number above 130, which is 12^{2}. <em>m</em> is 12, therefore the next consecutive even integer is 14.

12^{2}=144
144-14=130

The two consecutive integers are 12 and 14
5 0
4 years ago
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