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3 years ago

What is the common difference for this arithmetic sequence?

Mathematics

3 answers:

olya-2409 [2.1K]3 years ago

7 0

Subtract a number from the next number.

39 - 45 = -6

Answer: B. -6

Musya8 [376]3 years ago

5 0

B. -6
The numbers in the equation are decreasing meaning that the common difference must be a negative number.

Nettjordan2 years ago

0 0

2749 is my answer now now

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Lin has picked 1 ½ cups of raspberries, which is enough for ¾ of a cake. How many cups does she need for the whole cake?

Llana [10]

Okay. So, based off of that, if you divide 1 1/2 (3/2) by 3/4, 3/2 * 4/3 is 12/6 or 2. 1/2 cups of raspberries is needed for each fourth of the cake. 1/2 * 4 = 2. Lin will need 2 cups of raspberries for the whole cake.

6 0

3 years ago

What type of model best fits the height of a tree increases by 2.5 feet each growing season

Thepotemich [5.8K]

Answer:

Step-by-step explanation:

A linear graph with y values (height of tree) going up 2.5 with each increase of x (growing season)

This is the model that best fits the graph describing a growth of a plant

3 0

2 years ago

Maggie needs to spend at least six hours each week practicing the piano. She has already practiced three and one fourth hours th

Allisa [31]

Answer:

3 1/4 + 2x ≥ 6

Step-by-step explanation:

Let X equal the remaining time she needs to practice.

You would have 2x

The combined total needs to be 6 hours or greater.

You need to add the amount she already practiced to 2x.

Now you have: three and one fourth + 2x

This needs to be greater than or equal to 6.

I hope this helps you :)

6 0

3 years ago

A plane takes off from an airport and flies at a speed of 400km/h on a course of 120° for 2 hours. the plane then changes its co

butalik [34]

Answer:

Distance from the airport = 894.43 km

Step-by-step explanation:

Displacement and Velocity

The velocity of an object assumed as constant in time can be computed as

$\displaystyle \vec{v}=\frac{\vec{x}}{t}$

Where $\vec x$ is the displacement. Both the velocity and displacement are vectors. The displacement can be computed from the above relation as

$\displaystyle \vec{x}=\vec{v}.t$

The plane goes at 400 Km/h on a course of 120° for 2 hours. We can compute the components of the velocity as

$\displaystyle \vec{v_1}=$

$\displaystyle \vec{v_1}=\ km/h$

The displacement of the plane in 2 hours is

$\displaystyle \vec{x_1}=\vec{v_1}.t_1=.(2)$

$\displaystyle \vec{x_1}=km$

Now the plane keeps the same speed but now its course is 210° for 1 hour. The components of the velocity are

$\displaystyle \vec{v_2}=$

$\displaystyle \vec{v_2}=km/h$

The displacement in 1 hour is

$\displaystyle \vec{x_2}=\vec{v_2}.t_2=.(1)$

$\displaystyle \vec{x_2}=km$

The total displacement is the vector sum of both

$\displaystyle \vec{x_t}=\vec{x_1}+\vec{x_2}=+$

$\displaystyle \vec{x_t}=km$

$\displaystyle \vec{x_t}=$

The distance from the airport is the module of the displacement:

$\displaystyle |\vec{x_t}|=\sqrt{(-746.41)^2+492.82^2}$

$\displaystyle |\vec{x_t}|=894.43\ km$

8 0

3 years ago

Jacob and Ali want to run from one corner of a football field to the opposite corner. The rectangular football field is 50 yards

svet-max [94.6K]

Answer:

Jacob ran 40 yards more than Ali.

Step-by-step explanation:

Football field is in the shape of a rectangle having dimensions 120 yards × 50 yards

Since Jacob runs around the perimeter of the field from one corner to other corner, therefore, distance run by Jacob = $(\text{Length+width})$

Distance run by Jacob = 50 + 120 = 170 yards

Ali runs through the middle of the field diagonally on a straight line.

Therefore, distance covered by Ali = $\sqrt{\text{length}^{2}+\text{width}^{2}}$

= $\sqrt{(50)^{2}+(120)^{2}}$

= $\sqrt{2500+14400}$

= $\sqrt{16900}$

= 130 yards

Now difference between the distance covered by Jacob and Ali

= 170 - 130

= 40 yards

Therefore, Jacob ran 40 yards more than Ali.

7 0

2 years ago