Write any algebraic expression with at least two operations and the word phrase it represents

Mathematics

1 answer:

Lorico [155]4 years ago

8 0

Two consecutive numbers that are odd such that three times the first is 5 more than twice the second.

Solution. Let the first odd number be 2n + 1.

Then, the next one is 2n + 3 -- because it will be 2 more.

The problem says, that is, the equation is:

3(2n + 1) = 2(2n + 3) + 5.

That implies:

6n + 3 = 4n + 6 + 5 2n = 8 n = 4

Consequently, the first odd number is 2· 4 + 1 = 9.

The next one is 11.

According to the problem, that is the true solution. 3 · 9 = 2· 11 + 5.

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