Question

Write any algebraic expression with at least two operations and the word phrase it represents

Answer 1

Two consecutive numbers that are odd such that three times the first is 5 more than twice the second.

 

Solution. Let the first odd number be 2n + 1.

Then, the next one is 2n + 3 -- because it will be 2 more.

The problem says, that is, the equation is:

 

3(2n + 1) = 2(2n + 3) + 5.

That implies:

6n + 3 = 4n + 6 + 5 2n = 8 n = 4

Consequently, the first odd number is 2· 4 + 1 = 9.  

The next one is 11.
 

According to the problem, that is the true solution. 3 · 9 = 2· 11 + 5.