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4 years ago

Write any algebraic expression with at least two operations and the word phrase it represents

Mathematics

1 answer:

Lorico [155]4 years ago

8 0

Two consecutive numbers that are odd such that three times the first is 5 more than twice the second.

Solution. Let the first odd number be 2n + 1.

Then, the next one is 2n + 3 -- because it will be 2 more.

The problem says, that is, the equation is:

3(2n + 1) = 2(2n + 3) + 5.

That implies:

6n + 3 = 4n + 6 + 5 2n = 8 n = 4

Consequently, the first odd number is 2· 4 + 1 = 9.

The next one is 11.

According to the problem, that is the true solution. 3 · 9 = 2· 11 + 5.

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(-2x)^4 Simpify the number

Ivanshal [37]

Answer:

Step-by-step explanation:

i like ya cut g

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3 years ago

Simplify the following expression by combining like terms. Select the most simplified expression:

Fofino [41]

Answer:

A) 24 - 3p

Step-by-step explanation:

Distribute 6 through parenthesis

24 - 12p + 9p

then collect like terms

24 - 3p

8 0

3 years ago

Read 2 more answers

Maci and I are making a small kite. Two sides are 10". Two sides are 5". The shorter diagonal is 6". Round all your answers to t

Art [367]

Answer:

A. 4".

B. Approximately 9.54".

C. Approximately 13.54".

Step-by-step explanation:

Please find the attachment.

Let x be the distance from the peak of the kite to the intersection of the diagonals and y be the distance from the peak of the kite to the intersection of the diagonals.

We have been given that two sides of a kite are 10 inches and two sides are 5 inches. The shorter diagonal is 6 inches.

A. Since we know that the diagonals of a kite are perpendicular and one diagonal (the main diagonal) is the perpendicular bisector of the shorter diagonal.

We can see from our attachment that point O is the intersection of both diagonals. In triangle AOD the side length AD will be hypotenuse and side length DO will be one leg.

We can find the value of x using Pythagorean theorem as:

$(AO)^2=(AD)^2-(DO)^2$

$x^{2}=5^2-3^2$

$x^{2}=25-9$

$x^{2}=16$

Upon taking square root of both sides of our equation we will get,

$x=\sqrt{16}$

$x=\pm 4$

Since distance can not be negative, therefore, the distance from the peak of the kite to the intersection of the diagonals is 4 inches.

B. We can see from our attachment that point O is the intersection of both diagonals. In triangle DOC the side length DC will be hypotenuse and side length DO will be one leg.

We can find the value of y using Pythagorean theorem as:

$(OC)^2=(DC)^2-(DO)^2$

Upon substituting our given values we will get,

$y^2=10^2-3^2$

$y^2=100-9$

$y^2=91$

Upon taking square root of both sides of our equation we will get,

$y=\sqrt{91}$

$y\pm 9.539392$

$y\pm\approx 9.54$

Since distance can not be negative, therefore, the distance from intersection of the diagonals to the top of the tail is approximately 9.54 inches.

C. We can see from our diagram that the length of longer diagram will be the sum of x and y.

$\text{The length of the longer diagonal}=x+y$

$\text{The length of the longer diagonal}=4+9.54$

$\text{The length of the longer diagonal}=13.54$

Therefore, the length of longer diagonal is approximately 13.54 inches.

3 0

3 years ago

lemont has 30 books to pack the boxes each box holds 7 books if he fills each box how many boxes are left over

mariarad [96]

Answer:

2 books

Step-by-step explanation:

If 7 books= 1 box

Then 30 books= 30÷7= 4 boxes with a remainder of 2 books

Therefore books left over= 2 books

6 0

3 years ago

A norman window is constructed by adjoining a semicircle to the top of an ordinary rectangular. Find the dimensions of a norman

Yanka [14]

Answer:

$W\approx 8.72$ and $L\approx 15.57$ .

Step-by-step explanation:

Please find the attachment.

We have been given that a norman window is constructed by adjoining a semicircle to the top of an ordinary rectangular. The total perimeter is 38 feet.

The perimeter of the window will be equal to three sides of rectangle plus half the perimeter of circle. We can represent our given information in an equation as:

$2L+W+\frac{1}{2}(2\pi r)=38$