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3 years ago

Write any algebraic expression with at least two operations and the word phrase it represents

Mathematics

1 answer:

Lorico [155]3 years ago

8 0

Two consecutive numbers that are odd such that three times the first is 5 more than twice the second.

Solution. Let the first odd number be 2n + 1.

Then, the next one is 2n + 3 -- because it will be 2 more.

The problem says, that is, the equation is:

3(2n + 1) = 2(2n + 3) + 5.

That implies:

6n + 3 = 4n + 6 + 5 2n = 8 n = 4

Consequently, the first odd number is 2· 4 + 1 = 9.

The next one is 11.

According to the problem, that is the true solution. 3 · 9 = 2· 11 + 5.

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If on a scale 75 feet is represented by 1 inch, then a scale of 1/5 inch represents how many feet?

lara [203]

Answer:

15 feet

Step-by-step explanation:

if 1 inch represents 75 and it 1/5 then you do 75 divided by 5 and it gives you 15 so it represents 15 feet

8 0

3 years ago

I need to pass this question

stich3 [128]

Answer: -6 is your answer

5 0

2 years ago

Someone please help!

Luda [366]

g (f(-3)) = -6 is your answer

4 0

3 years ago

I’m the triangle shown below what is the approximate value of x

Dafna1 [17]

Answer:

The answer is choice B: 22.52 units.

Step-by-step explanation:

We use the Pythagoras's theorem which says for a right triangle with sides $x,y$ and hypotenuse $z$ :

$x^2+y^2=z^2.$

In our case

$z=26$

$y=13$

So we solve for $x:$

$x=\sqrt{z^2-y^2}=\sqrt{26^2-13^2} =\boxed{22.52\: units.}$

Which is choice B.

8 0

3 years ago

18 points - Qu. If 16 whole numbers factor into 120. You will see how 32 whole numbers factor into 1200 what does the same princ

alexandr402 [8]

Explanation:

Your premise and conclusion are both incorrect.

120 has the prime factorization ...

120 = 2³ × 3 × 5

The exponents of the prime factors are {3, 1, 1}. The number of divisors of 120 is the product of the increments of these numbers: (3+1)(1+1)(1+1) = 4·2·2 = 16.

120 has 16 natural-number divisors

1200 has the same prime factor and two more: 2·5, so the factorization is ...

1200 = 2⁴ × 3 × 5²

These exponents are {4, 1, 2} and the product of their increments is 5·2·3 = 30.

1200 has 30 natural-number divisors.

When a number is multiplied by 2, its number of natural-number divisors will be (n+1)/n times the previous number of divisors, where n is the increment of the exponent of 2 that is a factor of the original number.

For 120, 2^3 is the power of 2 that is a factor. So, multiplying the number by 2 multiplies the number of divisors by (4+1)/4 = 5/4.

240 will have 20 divisors versus the 16 that 120 has.

Likewise, multiplying this number (240) by 5 will multiply its number of divisors by (2+1)/(1+1) = 3/2, where 1 is the power of 5 that is a factor of 240.

1200 will have 20(3/2) = 30 divisors, versus the 20 that 240 has, or the 16 that 120 has.

Summary

The number of divisors of an integer is the product of the increments of the exponents of its prime factors.

_____

For reference

Here are the divisors of 120:

1, 2, 3, 4, 5, 6, 8, 10, 12, 15, 20, 24, 30, 40, 60, 120

Here are the divisors of 240:

1, 2, 3, 4, 5, 6, 8, 10, 12, 15, 16, 20, 24, 30, 40, 48, 60, 80, 120, 240

Here are the divisors of 1200:

1, 2, 3, 4, 5, 6, 8, 10, 12, 15, 16, 20, 24, 25, 30, 40, 48, 50, 60, 75, 80, 100, 120, 150, 200, 240, 300, 400, 600, 1200

7 0

3 years ago