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suter [353]
3 years ago
5

Write any algebraic expression with at least two operations and the word phrase it represents

Mathematics
1 answer:
Lorico [155]3 years ago
8 0

Two consecutive numbers that are odd such that three times the first is 5 more than twice the second.

 

Solution. Let the first odd number be 2n + 1.

Then, the next one is 2n + 3 -- because it will be 2 more.

The problem says, that is, the equation is:

 

<span> <span><span> <span> 3(2n + 1) </span> <span> = </span> <span> 2(2n + 3) + 5. </span> </span> </span></span>

That implies:

<span> <span><span> <span> 6n + 3 </span> <span> = </span> <span> 4n + 6 + 5 </span> </span> <span> <span> 2n = 8 n = 4

Consequently, the first odd number is 2· 4 + 1 = 9.  

The next one is 11.
 

According to the problem, that is the true solution. <span>3 · 9 = 2· 11 + 5.</span> </span> <span>   </span> <span>   </span> </span> </span></span>
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