Answer:
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The answer would be 28 and 1/4.
For this case we have the following arithmetic sequence:

To write in function form, we apply distributive property to the terms within parentheses:

Different signs are subtracted and the major sign is placed.
We simplify:

Answer:

Option C
Answer:
0.625
Step-by-step explanation:
Given that {A1, A2} be a partition of a sample space and let B be any event. State and prove the Law of Total Probability as it applies to the partition {A1, A2} and the event B.
Since A1 and A2 are mutually exclusive and exhaustive, we can say
b) P(B) = P(A1B)+P(A2B)
Selecting any one coin is having probability 0.50. and A1, A2 are events that the coins show heads.
c) Using Bayes theorem
conditional probability that it wasthe biased coin
=
d) Given that the chosen coin flips tails,the conditional probability that it was the biased coin=