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Naya [18.7K]
4 years ago
9

Jane is making a suit which requires 2 5⁄8 yards for the jacket and 1 3⁄4 yards for the skirt. What's the total amount of materi

al she needs? A. 3 1⁄2 yards B. 4 3⁄8 yards C. 3 2⁄3 yards D. 4 yards
Mathematics
1 answer:
Ann [662]4 years ago
7 0
The answer is B. 4 3⁄8 yards. The amount of material needed for the jacket is: x = 2 5/8 yd = 2 + 5/8 = 16/8 + 5/8 = (16+5)/8 = 21/8 yd. The amount of material needed for the skirt is: y = 1 3/4 yd = 1 + 3/4 = 4/4 + 3/4 = (4+3)/4 = 7/4 yd. The total amount of material Jane needs is: x + y = 21/8 + 7/4 = 21/8 + 14/8 = (21+14)/8 = 35/8 = (32+3)/8 = 32/8 + 3/8 = 4 + 3/8 = 4 3/8 yd.
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Suppose that the derivable functions x=x(t) and y=y(t) satisfy xcosy=2.
ololo11 [35]

Applying implicit differentiation, it is found that dy/dt when y=π/4 is of:

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<h3>What is implicit differentiation?</h3>

Implicit differentiation is when we find the derivative of a function relative to a variable that is not in the definition of the function.

In this problem, the function is:

xcos(y) = 2.

The derivative is relative to t, applying the product rule, as follows:

\cos{y}\frac{dx}{dt} - x\sin{y}\frac{dy}{dt} = 0

\frac{dy}{dt} = \frac{\cos{y}\frac{dx}{dt}}{x\sin{y}}

Since dx/dt=−2, we have that:

\frac{dy}{dt} = -2\frac{\cos{y}}{x\sin{y}}

When y = π/4, x is given by:

xcos(y) = 2.

x = \frac{2}{\cos{\frac{\pi}{4}}} = \frac{2}{\frac{\sqrt{2}}{2}} = \frac{4}{\sqrt{2}} \times \frac{\sqrt{2}}{\sqrt{2}} = 2\sqrt{2}

Hence:

\frac{dy}{dt} = -2\frac{\cos{y}}{x\sin{y}}

\frac{dy}{dt} = -\frac{1}{\sqrt{2}}\cot{y}

Since cot(pi/4) = 1, we have that:

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Which means that option a is correct.

More can be learned about implicit differentiation at brainly.com/question/25608353

#SPJ1

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