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3 years ago

How do you draw a picture of 1/6 of a whole- in -one Road

Mathematics

2 answers:

kirill [66]3 years ago

6 0

First draw six of anything take out one

brilliants [131]3 years ago

3 0

What do you mean by "in -one Road" ?

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I need help no ilnks please and thank you

Elza [17]

Answer:

yep

Step-by-step explanation:

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3 years ago

ABCD is a rectangle with diagonals segment AC and segment BD. If AC = 2х + 10 and BD -=56, find the value of х." О23О33О 78 O 12

Aleks04 [339]

Answer:

Step-by-step explanation:

The diagonals of a rectangle are equal.

2x + 10 = 56 That minus sign can't be there. Subtract 10 from both sides.

2x = 56 - 10 Combine

2x = 46 Divide by 2

x = 46/2

x = 23

7 0

2 years ago

A particle moves on a straight line and has acceleration a(t)=24t+2. Its position at time t=0 is s(0)=3 and its velocity at time

user100 [1]

Answer:

It's position at time t = 5 is 593.

Step-by-step explanation:

The velocity v(t) is the integral of the acceleration a(t)

The position s(t) is the integral of the velocity v(t)

We have that:

The acceleration is:

$a(t) = 24t + 2$

Velocity:

$v(t) = \int {a(t)} \, dt = \int {24t + 2} \, dt = 12t^{2} + 2t + K$

K is the initial velocity, that is v(0). Since V(0) = 13, K = 13

Then

$v(t) = 12t^{2} + 2t + 13$

Position:

$s(t) = \int {s(t)} \, dt = \int {12t^{2} + 2t + 13} \, dt = 4t^{3} + t^{2} + 13t + K$

Since s(0) = 3

$s(t) = 4t^{3} + t^{2} + 13t + 3$

What is its position at time t=5?

This is s(5).

$s(t) = 4t^{3} + t^{2} + 13t + 3$

$s(5) = 4*5^{3} + 5^{2} + 13*5 + 3$

$s(5) = 593$

It's position at time t = 5 is 593.

3 0

2 years ago

If i have 480 grams of pasta for 4 people how many kilograms will i need for 14 people

Afina-wow [57]

$\bf \begin{array}{ccll} \stackrel{pasta}{grams}&people\\ \text{\textemdash\textemdash\textemdash}&\text{\textemdash\textemdash\textemdash}\\ 480&4\\ g&14 \end{array}\implies \cfrac{480}{g}=\cfrac{4}{14}\implies \cfrac{480}{g}=\cfrac{2}{7} \\\\\\ \cfrac{480\cdot 7}{2}=g\implies 1680=g$

now, there are 1000 grams in one Kilogram, so in 1680 grams, there are 1680/1000 Kilograms, namely 1.680.

7 0

3 years ago

What is the length of the diagonal of a 10 foot by 8 foot rectangle?

zloy xaker [14]

Diagonal of a rectangle formula:

Diagonal = √l² + w²
Diagonal = √10² + 8²
Diagonal = √100 + 64
Diagonal = √164
Diagonal = 12.806 feet.

Or you can use the pythagorean theorem. The diagonal of a rectangle is the hypotenuse of a triangle.

a² + b² = c² ; where a and b represents the lengths of the triangle and c is the hypothenuse. In this case, the lengths are 10 ft and 8ft.

10² + 8² = 100 + 64 = 164 ; This represents c².
c = √c² = √164 = 12.806 ft

6 0

3 years ago