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kodGreya [7K]
2 years ago
10

Graph the equation below by plotting the y-intercept and a second point on the line. Y=3x-3

Mathematics
1 answer:
Zinaida [17]2 years ago
8 0

y-intercept is -3 so it must pass the vertical line -3.

Now start from point (0,-3) and rise up by 3, then go right by 1 since the slope is 3/1 or 3.

It should look like this:

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Answer:

Slope: -\frac{3}{4}

Y-intercept: 399

Slope-intercept form: y=-\frac{3}{4}x+399

Step-by-step explanation:

1. The equation in Standard form is given in the problem:

3y+4y=1596

2. Then, to write the equation of the line in slope-intercept form  y=mx+b, where <em>m</em> is the slope and <em>b</em> is the y-intercept, you must solve for <em>y</em> as you can see below:

4y=-3x+1596\\y=\frac{-3x+1596}{4}\\y=-\frac{3}{4}x+399

3. Therefore, the slope and the y-intercept are:

m=-\frac{3}{4}\\b=399

5 0
3 years ago
Write 83 as a sum of tens and ones
MrMuchimi
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