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Ivanshal [37]
3 years ago
14

If the following is a polynomial function, then state its degree and leading coefficient. If it is not, then state this fact. f(

x) = -13x^5 - 4x^4 - 1 Degree: 5; leading coefficient: -13 Degree: -13; leading coefficient: 5 Degree: 9; leading coefficient: -13 Not a polynomial function
Mathematics
1 answer:
Fed [463]3 years ago
5 0

By definition, a polynomial is an expression with more than one term. That is a monomial. We have names for 2-termed polynomials (binomials) and 3-termed polynomials (trinomials), but that's where the naming stops and they all are called polynomials after that. Our degree is the same as the highest exponent. So our degree is a fifth degree. The leading coefficient is the number that starts out the whole polynomial AS LONG AS IT IS IN STANDARD FORM. If our polynomial started with the -4x^4, our leading coefficient would NOT be -4 since the highest degree'd term will always come first in standard form. Your choice for your answer is the first one given. Degree: 5 Leading Coefficient: -13.

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Solve for x. 2(x + 14) + x = 70a. 11b. 12c. 14d. 17
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To solve for the variable x, we need to follow the rules of SADMEP. SADMEP is ONLY used when solving algebraic equations. SADMEP is an acronym for subtraction, addition, division, multiplication, exponents, and parentheses. Also, when solving for x, our main goal is to isolate x to one side of the equation.

2(x + 14) + x = 70 (use the distributive property)

2x + 28 + x = 70 (simplify - add)

3x + 28 = 70 (subtract 28 from both sides)

3x = 42 (divide both sides by 3)

x = 14

When solving ANY algebraic equation, we need check our answer. To check your answer, you substitute the x-value, which is 14 in this case, into the original equation and solve using PEMDAS.

2(x + 14) + x = 70 (substitute x = 14)

2(14 + 14) + 14 = 70 (simplify the terms inside the parentheses)

2(28) + 14 = 70 (simplify - multiply)

56 + 14 = 70 (simplify - add alike term)

70 = 70 | This is correct!

Therefore, your final answer is x = 14, which is choice C.

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